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Vanyuwa [196]
3 years ago
6

What are the center and radius of the circle defined by the equation x^2 y^2-6x 4y 4=0?

Mathematics
1 answer:
Kazeer [188]3 years ago
6 0
Please rewrite this equation of the circle correct with signs of minus or plus 
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What is the domain and range of f(x)=2.5x when x goes up to 800
Mandarinka [93]

Answer:

Domain:  all real numbers.  Range:  (-∞, 2000]

Step-by-step explanation:

f(x)=2.5x is a simple "ramp" function, a linear function and a polynomial.  As such, its domain contains "all real numbers."  That value 800 defines the largest value that this f(x) can have:  f(800) = 2.5(800)  = 2000.  

Thus, the range is "all real numbers from -∞ through and including 2000."

3 0
3 years ago
Please help. will give brainliest
Temka [501]

Answer:

84 sqmm

Step-by-step explanation:

hope it helps. ........።..

8 0
3 years ago
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What is the easiest way to solve a quadratic equation?​
algol [13]

Answer: This is an opinion, look below! :)

Step-by-step explanation:

Factor the expression. To factor the expression, you have to use the factors of the {\displaystyle x^{2}}x^{2} term (3), and the factors of the constant term (-4), to make them multiply and then add up to the middle term, (-11). Here's how you do it:

Since {\displaystyle 3x^{2}}3x^{2} only has one set of possible factors, {\displaystyle 3x}3x and {\displaystyle x}x, you can write those in the parenthesis: {\displaystyle (3x\pm ?)(x\pm ?)=0}(3x\pm ?)(x\pm ?)=0.

Then, use process of elimination to plug in the factors of 4 to find a combination that produces -11x when multiplied. You can either use a combination of 4 and 1, or 2 and 2, since both of those numbers multiply to get 4. Just remember that one of the terms should be negative, since the term is -4.[3]

By trial and error, try out this combination of factors {\displaystyle (3x+1)(x-4)}(3x+1)(x-4). When you multiply them out, you get {\displaystyle 3x^{2}-12x+x-4}3x^{2}-12x+x-4. If you combine the terms {\displaystyle -12x}-12x and {\displaystyle x}x, you get {\displaystyle -11x}-11x, which is the middle term you were aiming for. You have just factored the quadratic equation.

As an example of trial and error, let's try checking a factoring combination for {\displaystyle 3x^{2}-11x-4=0}3x^{2}-11x-4=0 that is an error (does not work): {\displaystyle (3x-2)(x+2)}(3x-2)(x+2) = {\displaystyle 3x^{2}+6x-2x-4}3x^{2}+6x-2x-4. If you combine those terms, you get {\displaystyle 3x^{2}-4x-4}3x^{2}-4x-4. Though the factors -2 and 2 do multiply to make -4, the middle term does not work, because you needed to get {\displaystyle -11x}-11x, not {\displaystyle -4x}-4x.

7 0
3 years ago
Task: Population of a Species
Cloud [144]

Answer:

C(t) = 20t

Step-by-step explanation:

The graph of C(t) appears to be linear

The y intercept is 0

The slope is 200/10 = 20

y = mx+b  where m is the slope and b is the y intercept

y = 20x+0

y = 20x

C(t) = 20t

4 0
2 years ago
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Simplify the expression 1+4.25n+3/2p-3+(-2p)+5/4n
ale4655 [162]

The answer is 5.5n-0.5p-4

4 0
3 years ago
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