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Volgvan
3 years ago
11

A student titrates 10.00 milliliters of hydrochloric acid of unknown molarity with 1.000 m naoh. it takes 21.17 milliliters of b

ase to exactly neutralize the acid. if the student follows the rules for significant figures in determining the molarity of the acid, what should her answer be
Chemistry
1 answer:
Dima020 [189]3 years ago
4 0
Mole ratio for the reaction is 1:1
no of moles in NaOH that reacted= 1*21.17/1000=0.02117mols
 molarity of HCl=0.02117*10/1000
                         =2.117M
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1.83 × 10⁻⁷ mol Au

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<u>Step 1: Define</u>

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<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.60 \cdot 10^{-5} \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
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