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3 years ago

Is elemental sulfur a pure substance

Chemistry

1 answer:

Valentin [98]3 years ago

7 0

Answer:

All elements are pure substances. So yes it is.

Explanation:

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In a chemical equation, which symbol should be used to indicate that a substance is in solution?

lisov135 [29]

Example :

$2FeCl_3_{(aq)}+2KI_{(aq)}=2FeCl2_{(aq)}+2KCl_{(aq)}+I_2_{(s)}$

If you use the subscript (aq) (=aquaris) , this means that the substance is in a solution.

Subscripts:
-aq-this means that the substance is in a solution
-s-this means that the substance is a solid(or precipitate)
-l-this means that the substance is a liquid
-g-this means that the subtance is a gas

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3 years ago

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It is C. because the sunlight bounces off the moon causing it to be visible only at night.

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How could you ensure that all the spectroscopes used the same calibration line and equation? What would you need to be sure was

NISA [10]

People had asked this many times and that is why they came up with methods and standards that will answer these type of questions. You can look it up in the NIST or the National Institute for Standards and Technology.

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2 years ago

How many moles of atoms are in 5.00 g of 13C

Illusion [34]

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3 years ago

A dilute solution of bromine in carbon tetrachloride behaves as an ideal-dilute solution. The vapour pressure of pure CCl4 is 33

ANEK [815]

Explanation:

The given data is as follows.

Vapour pressure of pure $CCl_{4}$ = 33.85 Torr

Temperature = 298 K

Mole fraction of $Br_{2}$ = 122.36 torr

Therefore, calculate the vapor pressure of $Br_{2}$ as follows.

Vapour pressure of $Br_{2}$ = mole fraction of $Br_{2}$ x K of $Br_{2}$

= 0.050 x 122.36 Torr

= 6.118 Torr

So, vapor pressure of $Br_{2}$ is 6.118 Torr .

Now, calculate the vapor pressure of carbon tetrachloride as follows.

Vapour pressure of $CCl_{4}$ = mole fraction of $CCl_{4}$ x Pressure of $CCl_{4}$

= (1 - 0.050) × 33.85 Torr

= 32.1575 Torr

So, vapor pressure of $CCl_{4}$ is 32.1575 Torr .

Hence, the total pressure will be as follows.

= 6.118 Torr + 32.1575 Torr

= 38.2755 Torr

Therefore, composition of $CCl_{4}$ = $\frac{32.1575 Torr}{38.2755 Torr}$

= 0.8405

Composition of $CCl_{4}$ is 0.8405 .

And, composition of $Br_{2}$ = $\frac{6.118 Torr}{38.2755 Torr}$

= 0.1598

Composition of $Br_{2}$ is 0.1598 .

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3 years ago