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Angelina_Jolie [31]
3 years ago
11

What describes the basis of the band theory of metallic bonding

Chemistry
1 answer:
Serjik [45]3 years ago
6 0
Metals have their valence band filled, and due to the absence of a band gap, their conduction band partially filled.


The theory predicts that metals will conduct (both heat and) electricity very well and so is generally accepted.
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Critical Thinking: How are Volcanoes connected to the formation of the atmosphere and oceans????
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Why do atoms combine in an ionic bond
victus00 [196]

Answer:

Ionic bonds are formed through the exchange of valence electrons between atoms, typically a metal and a nonmetal. The loss or gain of valence electrons allows ions to obey the octet rule and become more stable. Therefore, ions combine in ways that neutralize their charges.

Explanation:

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3 years ago
The reaction na 3po 4( aq) 3 agno3( aq) → ag 3po 4( s) 3 nano 3( aq) is best classified as a(n):_____.
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The reaction  Na_{3} PO_{4} ( aq) +3AgNO_{3} (aq) → Ag_{3} PO_{4} ( aq) +3NaNO_{3} (aq) is best classified as double displacement reaction.

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6 0
1 year ago
A student places a 100.0°C piece of metal that weighs 85.5 g into 122 mL of 16.0°C water. If the final temperature is 20.2°C, wh
Musya8 [376]

Answer:

The specific heat of the metal is 0.314 J/g°C

Explanation:

Step 1: data given

Temperature of the piece of metal = 100.0 °C

Mass of the metal = 85.5 grams

Volume of water = 122 mL = 122 grams

Temperature of water = 16.0 °C

The final temperature of water = 20.2 °C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of metal

Heat gained= heat lost

Qgained = - Qlost

Qwater = -Qmetal

Q = m*c* ΔT

m(metal)*c(metal)*ΔT(metal) = -m(water)*c(water)*ΔT(water)

⇒m(metal) = mass of metal = 85.5 grams

⇒c(metal) = the specific heat of metal = TO BE DETERMINED

⇒ΔT(metal) = the change of temperature of metal = T2 - T1 = 20.2 - 100 °C =  -79.8 °C

⇒m(water) = the mass of water = 122 grams

⇒c(water) = the specific heat of water = 4.184 J/g°C

⇒ΔT(water) = the change of temperature of metal = T2 - T1 = 20.2 - 16.0 °C =  4.2 °C

85.5 *c(metal) * -79.8 = -122 * 4.184 * 4.2

c(metal) * (-6822.9) = -2143.9

c(metal) = 0.314 J/g°C

The specific heat of the metal is 0.314 J/g°C

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How does the jet stream influence weather?
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