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Angelina_Jolie [31]

2 years ago

11

What describes the basis of the band theory of metallic bonding

1 answer:

Serjik [45]2 years ago

6 0

Metals have their valence band filled, and due to the absence of a band gap, their conduction band partially filled.

The theory predicts that metals will conduct (both heat and) electricity very well and so is generally accepted.

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At room temperature (208C) and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha

Ugo [173]

Total density of filled ball with nitrogen gas: $\frac{0.12G+0.6524g}{0.560L} = 1.3792g/L$

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air. Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = $d_4=1.165g/L$

Mass of the nitrogen gas : $1.165g/L \times 0.560L = 0.6524g$

Learn more about Mass and Density here:

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4 0

1 year ago

Determina el pH del café cuya concentración de H+ es de 0.00001M

lara31 [8.8K]

Answer:

5

Explanation:

Given parameters:

Hydrogen ion concentration = 0.00001M

Unknown:

pH of the solution =?

Solution:

The pH is used to estimate the degree of acidity or alkalinity of a solution. To solve for pH of any solution, we use the expression below;

pH = -log [H⁺]

[H⁺] is the hydrogen ion concentration

pH = -log (1 x 10⁻⁵)

pH = -(-5) = 5

4 0

3 years ago

Exactly 25.0 mL of an aqueous solution of barium hydroxide required 32.0 mL of 0.200 M nitric acid to neutralize it. What is the

Brrunno [24]

Answer:

2000m the example 25.0\0.200

7 0

2 years ago

Read 2 more answers

1 question you still have about the concept

allochka39001 [22]

Answer:

what concept?

Explanation:

5 0

2 years ago

Read 2 more answers

Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.

Jlenok [28]

<u>Answer:</u> The density of gold in $g/cm^3$ is $19.22g/cm^3$

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

$\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}$

We are given:

Density of gold = $1200lb/ft^3$

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into $g/cm^3$ , we get:

$\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3$

Hence, the density of gold in $g/cm^3$ is $19.22g/cm^3$

6 0

3 years ago