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BartSMP [9]
3 years ago
5

Please help me with my work​

Chemistry
2 answers:
Paul [167]3 years ago
6 0

Answer:

2

Explanation:

There's 2 Hydrogen and Chlorine molecules on the right side with one Zinc. So the left side needs to have a coefficient of 2 on the hydrochloric acid, or HCl.

lidiya [134]3 years ago
4 0
D. 2

Explanation:

To be balanced, the hydrogen and chlorine atoms are both 2 and 2 in the products side. Hence, we must add a two to the HCl in order to have 2 hydrogens and 2 chlorines in the reactants.

Hope this helps, brainliest would be appreciated :)
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effect. RbClO(s) → Rb+(aq) + ClO−(aq) HClO(aq) + H2O(l) equilibrium reaction arrow H3O+(aq) + ClO−(aq) The degree of dissociatio
Lemur [1.5K]

Explanation:

Common ion effect is defined as the effect which occurs on equilibrium when a common ion (an ion which is already present in the solution) is added to a solution. This effect generally decreases the solubility of a solute.

Equilibrium reaction of strontium sulfate and sodium sulfate follows the equation:

RbClO(s)\rightarrow Rb^{+}(aq.)+ClO^{-}(aq.)

HClO(aq)+H_2O\rightleftharpoons H_3O^+(aq.)+ClO^{-}(aq.)

According to Le-Chateliers principle: If there is any change in the variables of the reaction, the equilibrium will shift in the direction in order to minimize the effect.

In the equilibrium reactions, hypochlorite ion is getting increased on the product side, so the equilibrium will shift in the direction to minimize this effect, which is in the direction of hydrogen hypochlorite.

Thus, the addition hypochlorite ions will shift the equilibrium in the left direction.

The dissociation of hydrogen hypochlorite is suppressed due to the common ion effect.

8 0
4 years ago
Given the balanced equation 2C4H10 + 13O2 → 8CO2 + 10H2O, how many moles of CO2 are produced when 14.9g of O2 are used?
Anna [14]

Answer: The number of moles of CO_2 produced are, 0.287 moles.

Explanation : Given,

Mass of O_2 = 14.9 g

Molar mass of O_2 = 32 g/mol

First we have to calculate the moles of O_2

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}

\text{Moles of }O_2=\frac{14.9g}{32g/mol}=0.466mol

Now we have to calculate the moles of CO_2

The balanced chemical equation is:

2C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2

From the reaction, we conclude that

As, 13 mole of O_2 react to give 8 moles of CO_2

So, 0.466 mole of O_2 react to give \frac{8}{13}\times 0.466=0.287 mole of CO_2

Therefore, the number of moles of CO_2 produced are, 0.287 moles.

3 0
3 years ago
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