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3 years ago

I NEED HELP ASAP PLEASE PLOT IT BY DRAWING IT

Mathematics

1 answer:

IRISSAK [1]3 years ago

3 0

Answer:

-1 1/2= 2 lines to the left of -1

1 1/4= 1 line to the right of 1

I hope this helps!

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Kayden is the youngest of four siblings whose ages are consecutive integers. if the sum of their ages is 90, find kayden's age.

NISA [10]

Based on the fact that Kayden is the youngest and their ages are consecutive and add up to 90, the Kayden is 21.

<h3>How old is Kayden?</h3>

To find Kayden's age, assume that it is x and use the formula:

90 = x + (x + 1) + (x +2) + (x +3)

Solving for x gives:

90 = 4x + 6

4x = 90 - 6

x = 84 / 4

x = 21

Find out more on solving for age at brainly.com/question/11757623

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6 0

1 year ago

Use cylindrical coordinates to evaluate the triple integral ∭ where E is the solid bounded by the circular paraboloid z = 9 - 16

4vir4ik [10]

Answer:

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

Step-by-step explanation:

The Cylindrical coordinates are:

x = rcosθ, y = rsinθ and z = z

From the question, on the xy-plane;

$9 -16 (x^2 + y^2) = 0 \\ \\ 16 (x^2 + y^2) = 9 \\ \\ x^2+y^2 = \dfrac{9}{16}$

$x^2+y^2 = (\dfrac{3}{4})^2$

where:

0 ≤ r ≤ $\dfrac{3}{4}$ and 0 ≤ θ ≤ 2π

∴

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} \int ^{9-16r^2}_{0} \ r \times rdzdrd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 z|^{z= 9-16r^2}_{z=0} \ \ \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 ( 9-16r^2}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} ( 9r^2-16r^4}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( \dfrac{9r^3}{3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3r^3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) d \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) \theta |^{2 \pi}_{0}$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{64}}-\dfrac{243}{320}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{160}})2 \pi$

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

4 0

3 years ago

PLZ HELP 67 POINTS. 1 + 1<br>

Arada [10]

Answer:

100% its 2 my guy trust meeee

7 0

2 years ago

Read 2 more answers

You roll a six-sided die. Find the probability of each event.

kirill [66]

Answer:

The probability of rolling an answer less than 5 is 66.7 percent

Step-by-step explanation:

5 0

2 years ago

Find the slope of (2,3) and (6,7)

Brut [27]

To find the slope, we must use the formula stated below.

Slope = Change in Y / Change in X = (Y1 - Y2) / (X1 - X2)

Since our coordinates are given as (X, Y), we must pick a coordinate to be #1, and the other coordinate will be #2.

I'll use the first coordinate as our #1.

(3 - 6) / (2 - 7) = (-3) / (-5) = 3/5 which is our answer

6 0

3 years ago