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Vanyuwa [196]
3 years ago
13

Enter your answer in the provided box. How many unpaired electrons are present in the ground state of the atoms in Group 6A(16)

Chemistry
1 answer:
Nat2105 [25]3 years ago
6 0

Answer:

Two unpaired electrons

Explanation:

The elements of group 16 include; oxygen, sulphur, selenium, tellurium etc. These elements contain six electrons on their outermost shells. These six electrons are comprised of two lone pairs and two unpaired electrons. The outermost electron configuration of group 16 elements is ns2np4.

Let us take a well known example, look at the formation of water. Oxygen contains two lone pairs of electrons and two unpaired electrons which are used to bond to two hydrogen atoms to form H2O. Similar hydrides are formed with other group 16 elements.

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How many grams of product are formed from 2.0 mol of N2 (g) and 8.0 mol of Mg(s)? Show all calculations leading to an answer. Li
Vaselesa [24]

Balanced chemical reaction happening here is:

3Mg(s) + N₂(g) → Mg₃N₂(s)        


 <u>moles of product formed from each reactant:</u>


2.0 mol of N2 (g) x <u> 1 mol Mg₃N₂      </u>  = <u>2 mol Mg₃N₂</u>

                                    1 mol N2

and


8.0 mol of Mg(s) x <u> 1 mol Mg₃N₂      </u>   = 2.67 mol Mg₃N₂

                                 3 mol Mg


Since N2 is giving the least amount of product(Mg₃N₂) ie. 2 mol Mg₃N₂

N2 is the limiting reactant here and Mg is excess reactant.


Hence mole of product formed here is 2 mol Mg₃N₂    


molar mass of Mg₃N₂    

= 3 Mg + 2 N

= 101g/mol  


mass of product(Mg₃N₂) formed  

= moles x Molar mass

= 2 x 101

= 202g Mg₃N₂


<u>202g of product are formed from 2.0 mol of N2(g) and 8.0 mol of Mg(s).</u>


<u>   </u>   The following are indicators of chemical changes:

Change in Temperature    

Change in Color

Formation of a Precipitate



8 0
3 years ago
A sample of seawater weighs 158 g and has a volume of 156 mL. What is the density, in g/
nirvana33 [79]

1.01 g/ml

<em>Hope this helps</em><em> </em><em>:</em><em>)</em>

3 0
4 years ago
Which statement best describes the use of catalytic converters in automobiles?
Stells [14]

Answer:

The statement that best describes the use of catalytic converters in automobiles is;

They oxidize hydrocarbons to form less toxic gases

Explanation:

Catalytic converters

A working engine produces some air pollutants which are made due to fuel not completely burnt in the engine, including unburnt gasoline (a hydrocarbon), nitrogen oxides, and carbon monoxide

Carbon monoxide is poisonous to breathe in if present in the air around us, and nitrogen oxides causes acid rain and smog, while hydrocarbon from the gasoline causes smog

The catalyst in the catalytic converters aids in the conversion of the harmful gases produced by the car engine into harmless gases such as the types of gases already existing in the atmosphere and therefore, can be released into the air

The catalysts in the catalytic converter work by either oxidizing some of the harmful gases such as the unburnt hydrocarbons, or by reducing the other harmful gases such as the nitrogen oxides.

Therefore, the statement that best describes the use of catalytic converters in automobiles is that they oxidize hydrocarbons to form less toxic gases

8 0
3 years ago
Read 2 more answers
Compare earths compositional layers with its structural layer
kykrilka [37]

Answer:

The Earth has different compositional and mechanical layers. Compositional layers are determined by their components, while mechanical layers are determined by their physical properties. The outermost solid layer of a rocky planet or natural satellite. Chemically distinct from the underlying mantle.

4 0
3 years ago
Started: Feb 22 at 92
aliina [53]

Answer:

1272 pound

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = 38 psi

Area (A) = 12 cm by 18 cm

Force (F) =?

Next, we shall determine the area. This can be obtained as follow:

Area (A) = 12 cm by 18 cm

A = 216 cm²

Next, we shall convert 216 cm² to square inch (in²). This can be obtained as follow:

1 cm² = 0.155 in²

Therefore,

216 cm² = 216 cm² × 0.155 in² / 1 cm

216 cm² = 33.48 in²

Finally, we shall determine the force exerted. This can be obtained as follow:

Pressure (P) = 38 psi = 38 lbf/in²

Area (A) = 33.48 in²

Force (F) =?

P = F/A

38 = F / 33.48

Cross multiply

F = 38 × 33.48

F = 1272 pound

Thus, the force exerted is 1272 pound

7 0
3 years ago
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