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2 years ago

Which value gives the number of particles in 1 mol of a substance?

1 answer:

7 0

The number of particles (molecules or atoms) is: 6.022 x 10²³ particles (atoms or molecules).

1 mol of H₂O has 6.022 x 10²³ molecules.
1 mol of Al has 6.022 x 10²³ atoms.

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Please help, and I’ll thank you.

coldgirl [10]

Answer:

There will be formed 13.82 grams of Fe3O4.

Explanation:

Step 1: the balanced reaction

3 Fe(s) + 4 H2O(l) —— Fe3O4(s) + 4 H2(g)

We see that for 3 moles Fe consumed, there will be consumed 4 moles of H20 and produced 1 mole of Fe3O4 and 4 moles of H2.

Step 2: Calculating moles

⇒mole = mass / Molar mass

⇒moles Fe = 10g / 55.845g/mole = 0.179 moles

⇒moles H2O = 10g / 18g/mole = 0.5556 moles

Since we have 4 moles of H2O consumed for 3 moles of Fe, this means that for 0.179 moles of Fe, we have :

0.179 / 4 *3 = 0.2387 moles of H2O consumed

This means that Fe will be completely consumed and there will remain 0.2387 moles of H2O.

Fe is the limiting reactant and H2O is in excess.

Step 3: Calculate moles of Fe3O4

For 3 moles of Fe consumed, we have 1 mole of Fe3O4 produced.

This means, that for 0.179 moles of Fe consumed, we have 0.179/3 =0.05967 molesof Fe3O4 produced.

Step 4: Calculating mass of Fe3O4

mass= number of moles * Molar mass

mass Fe3O4 = 0.05967 mole * 231.55g/mole = 13.8166 g ≈ 13.82grams of Fe3O4

There will be formed 13.82 grams of Fe3O4.

5 0

3 years ago

How much energy is required to boil 65 grams of 100°C water And then heat the steam to 150°C?

Artyom0805 [142]

Answer:

13598 J

Explanation:

Q = m × c × ∆T

Where;

Q = amount of energy (J)

m = mass (grams)

c = specific heat capacity

∆T = change in temperature

m = 65g, specific heat capacity of water = 4.184J/g°C, initial temperature= 100°C, final temperature = 150°C

Q = 65 × 4.184 × (150 - 100)

Q = 271.96 × 50

Q = 13598 J

Hence, 13598 J of energy is required to boil 65 grams of 100°C water and then heat the steam to 150°C.

8 0

3 years ago

study figure 10-3. how much nitrogen-14 will be produced from a 200-g sample of carbon 14 after 17,190 years

Amanda [17]

For this problem, we use the formula for radioactive decay which is expressed as follows:

An = Aoe^-kt

where An is the amount left after time t, Ao is the initial amount and k is a constant.

We calculate as follows:

An = Aoe^-kt
0.5 = e^-k(5730)
k = 1.21x10^-4

An = Aoe^-kt
An = 200e^-1.21x10^-4(17190)
An = 25

Therefore, about 175g is produced.

8 0

3 years ago

Enter an equation for the formation of CaCO3(s) from its elements in their standard states. Enter any reference to carbon as C(s

kaheart [24]

Answer:

CaF2 + CO3- ----> CaCO3 + 2 F-

Explanation:

The chemical compounds found on the left side of the date are the reagents and those found on the right are the products, where calcium carbonate appears.

Calcium carbonate is a quaternary salt

6 0

2 years ago

For the reaction X_2+ Y + Z → XY + XZ, it is found that the rate equation is rate = k [X_2][Y]. Which of the following might exp

iogann1982 [59]

Answer: C. Z is an intermediate.

Explanation: The given reaction is $X_{2} + Y + Z \rightarrow XY + XZ$

And the rate equation is rate = k [X_2][Y]

From this, we can imply that either the concentration of Z is very small in comparison tot he other reactants or the reactant Z is an intermediate which is available only for the given small amount of time.

There can be various steps in the mechanism for the proposed reaction and Z can also react in any of the steps. It is not necessary that it should react in a step other than the rate determining step.

This might be possible that the activation energy for Z to react is very low But since it has made a new kind of product that is XZ, then the former cannot be true.

3 0

2 years ago