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Cloud [144]
3 years ago
6

Briefly discuss interpretations of your observations and results. Discuss how your observations illustrated LeChatelier's princi

ple. Discuss how reactant concentrations change as equilibrium reactions shift to the left or the right. Likewise, discuss how product concentrations change as equilibrium reactions shift to the left and the right. Explain using your observations in Part V if you would prepare a calcium oxalate precipitate in acidic or basic solution.
Chemistry
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

Le Chatelier's principle can be applied in explaining the results

Explanation:

According to Le Chatelier's principle, when a constraint such as a change in concentration in this case is imposed on a chemical system in equilibrium, the system will adjust itself in such a way as to annul the constraint imposed.

Hence, when the color of the solution was more like that of the control, the reaction would shift towards the left. Similarly, when the color was more like it was towards the reactant, the reaction would shift towards the right.

If we were to prepare calcium oxalate, we should prepare it in a base solution. This is because when the base was added to calcium oxalate, it did not form any precipitate but when an acid was added to the calcium oxalate, it formed a precipitate.

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Which of the following will increase the volume of a gas?
Dmitry_Shevchenko [17]

Answer:

B. Decreasing the pressure applied to the gas molecules

Explanation:

According to Boyle's Law, the pressure of the gas is inversely proportional to the volume of the gas. So, the option B is correctly implied to it.

Other values such as Temperature, Number of molecules are inversely proportional to the volume of the gas.

Size of the gas molecules is negligible as compared to volume.

7 0
3 years ago
Ok, got it!!! thank you so much
bekas [8.4K]
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7 0
3 years ago
URGENT!!! What is the concentration in moles per litre of a solution that contains 7.68 g of H2SO4 in 150.0 mL of water?
hichkok12 [17]

Answer: 0.5225 mcl/l

Explanation:

5 0
3 years ago
2. Given the unbalanced equation:
zheka24 [161]
2 Na + 2 H2O → 2 NaOH + H2 (balanced equation)
The answer would be 2, since 2 in the coefficient of both Na and NaOH
7 0
3 years ago
SnO2 + 2 H2 ——> Sn + 2 H2O
SpyIntel [72]

Answer:

0.15g

Explanation:

Given parameters:

Number of molecules of water = 1.2 x 10²¹ molecules

Unknown:

Mass of SnO₂  = ?

Solution:

To solve this problem, we have to work from the known to the unknown specie;

             SnO₂   +    2H₂    →   Sn  +   2H₂O

Ensure that the equation given is balanced;

       

Now,

          the known species is water;

                  6.02 x 10²³ molecules of water  = 1 mole

                   1.2 x 10²¹ molecules of water  = \frac{1.2 x 10^{21} }{6.02 x 10^{23} }    = 0.2 x 10⁻²moles

Number of moles of water  = 0.002moles

           From the balanced chemical equation:

         

             2 mole of water is produced from 1 mole of    SnO₂  

           0.002 moles of water will be produced from \frac{0.002}{2}  = 0.001moles

To find the mass;

           Mass  = number of moles x molar mass

Molar mass of  SnO₂ = 118.7 + 2(16) = 150.7g/mol

        Mass  =  0.001 x 150.7 = 0.15g

3 0
3 years ago
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