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umka2103 [35]
3 years ago
6

What does a scientist observe in a chemical's reaction rate?

Chemistry
2 answers:
defon3 years ago
7 0

The scientist observes at what rate is the concentration increasing or decreasing.

Softa [21]3 years ago
7 0

Answer:

The speed at which the reactants change to products over a given time.

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3<br> 3) Write any 4 important of<br> 4 important of measurement <br> Science
kramer

Answer:

A measurement is the action of measuring something, or some amount of stuff. So it is important to measure certain things right, distance, time, and accuracy are all great things to measure. Measurements can also allow us to make desicions based on the outcome of the measurement

7 0
3 years ago
Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a
coldgirl [10]

The final temperature, t₂ = 30.9 °C

<h3>Further explanation</h3>

Given

24.0 kJ of heat = 24,000 J

Mass of calorimeter = 1.3 kg = 1300 g

Cs = 3.41 J/g°C

t₁= 25.5 °C

Required

The final temperature, t₂

Solution

Q = m.Cs.Δt

Q out (combustion of compound) = Q in (calorimeter)

24,000 = 1300 x 3.41 x (t₂-25.5)

t₂ = 30.9 °C

3 0
3 years ago
Read 2 more answers
What are the reactants found in soap and detergents?
babymother [125]

https://www.britannica.com/science/soap/Raw-materials



8 0
3 years ago
Read 2 more answers
Ricardo is working on a refrigeration system and needs to know the fluid pressure of a water tank. He knows that the tank is 12
hjlf

Answer:

I also have this question but see the 69 page of ur question book

8 0
3 years ago
The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga
Rashid [163]

Answer:

Final temperature of the gas is  576 ^{0}\textrm{C}.

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

                                       \frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

where V_{1} and V_{2} are volume of gas at T_{1} and T_{2} temperature (in kelvin scale) respectively.

Here V_{1}=158mL , T_{1}=(273+25)K=298K and V_{2}=450mL

So  T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K 

849 K = (849-273) ^{0}\textrm{C} = 576 ^{0}\textrm{C}

So final temperature of the gas is  576 ^{0}\textrm{C}.

3 0
3 years ago
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