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3 years ago

(-2)^2-(-8)*[(-2)-(-10)]

1 answer:

7 0

Greetings!

"How to solve $(-2)^2-(-8)*[(-2)-(-10)]$ "...

Follow PEDMAS:
$(-2)^2-(-8)*[(-2)-(-10)]$
$=(-2)^2-(-8)*[(-2)+(10)]$
$=(-2)^2-(-8)*(8)$
$=4-(-8)*(8)$
$=4-(-64)$
$=4+64$
$=68$

The answer would be 68.

Hope this helps.
-Benjamin

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2 years ago

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Step-by-step explanation:

We have the system of equations:

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y = -x + 4

Now we have two lines, and we can just graph them, the easiest way is the replace the value of x and obtain two points that belong to the line, and then draw a line that passes through both lines.

For example with the first one, we can firt replace x by 0 to get:

y = 2*0 - 2

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Then the point (0, -2) belongs to this line.

Now we can replace x by 1 to get:

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Then we can draw these two points in the graph, and just draw a line that passes through these two points.

Once you have your two lines drawn, the solution of the system will be the point in which the lines intersect.

Below, you can see the two lines graphed (the green is the first one and the red is the second one)

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