Question

(-2)^2-(-8)*[(-2)-(-10)]

Answer 1

Greetings!

"How to solve $(-2)^2-(-8)*[(-2)-(-10)]$"...

Follow PEDMAS:
$(-2)^2-(-8)*[(-2)-(-10)]$
$=(-2)^2-(-8)*[(-2)+(10)]$
$=(-2)^2-(-8)*(8)$
$=4-(-8)*(8)$
$=4-(-64)$
$=4+64$
$=68$

The answer would be 68.

Hope this helps.
-Benjamin