Answer:
ok i will
Step-by-step explanation:
Answer:
1/4 divided by 1/2 equals 1/2
Real-world problem:
A constructor official knows that he needs 1/2 sack of cement to produce 10 blocks of concrete for a wall. The official only has 1/4 of the sack left and want to know how many blocks he can produce with this material.
Step-by-step explanation:
Since you know that 1/2 of the sack is needed to make 10 blocks, you can use this information to find the number of blocks that 1/4 of a sack can make. The question you want to answer is:
if 
of a sack produces 10 blocks, how may blocks 
of a sack can produce?
Using the Rule of Three you can solve
Now you know that 1/4 of a sack can produce 1/2 the number of blocks that 1/2 of the sack can produces, this means that you can produce 5 blocks of concrete.
There is only 1 remaining side
We have 2 sides and an included angle, we use the Law of Cosines to solve the third side:
c^2 = a^2 + b^2 -2ab *cos(C)
c^2 = .5^2 + .333333333...^2 - 2 * .5 * .3333333... * cos (95)
c^2 = .25 + .1111111111111111... -2*.5*.3333333333...* -0.087156
c^2 = 0.3611111111 + 0.029052
c^2 = 0.3901631111
c = 0.6246303796
Answer:
1
Step-by-step explanation:
Given :
Mean, μ = 4
Standard deviation, s = 0.8
Sample size, n = 30
The distribution is independent.
Z = (x - μ) / s /sqrt(n)
Probability that downtime period is between 1 and 5
P(1≤ x ≤ 5) :
[(x - μ) / (s /sqrt(n))] ≤ Z ≤ [(x - μ) / (s /sqrt(n))]
[(1 - 4) / (0.8 /sqrt(30))] ≤ Z ≤ [(5 - 4) / (0.8 /sqrt(30)]
[-3 / 0.1460593] ≤ Z ≤] 1 / 0.1460593]
P(-20.539602 ≤ Z ≤ 6.8465342)
P(Z ≤ 6.8465342) - P(Z ≤ - 20.5396)
P(Z ≤ 6.8465342) = 1 (Z probability calculator)
P(Z ≤ - 20.5396) = 0 (Z probability calculator)
1 - 0 = 1
