Let x be larger integer so x-3 is the smaller
so x^2+ x-3 = 87
x^2 +x -90=0 and factor
(x-9)(x+10)=0
x=9 or x=-10 but x must be positive
so x=9 and smaller number is 6
Answer:
any digit 0 to 9
Step-by-step explanation:
Nothing about your description of the number suggests that the 10s digit depends on the units digit. The tens digit can be any digit 0 to 9.
Answer:
A 3^4 * 3^-4 / 3^6
C 1 / 3^6
Step-by-step explanation:
( 3^2 * 3^-2)
------------------- all the the power of 2
3^3
First simplify the numerator
We know a^b* a^c = a^(b*c)
( 3^(2+-2))
------------------- all to the power of 2
3^3
( 3^(0))
------------------- all to the power of 2
3^3
( 3^(0))
------------------- all to the power of 2
3^3
We know a^b/ a^c = a^(b-c)
3^(0-3) all to the power of 2
3^-3 all to the power of 2
3^-3 ^2
We know that a^b^c = a^(b*c)
3^(-3*2)
3^ -6
We know the negative exponent takes if from the numerator to the denominator
1 / 3^6
The other correct choice is A
3^4 * 3^-4 = 3^0 which is 1
1/3^6 is the same answer
Answer:
x = 6
Step-by-step explanation:
Love proportions!
3x+2(x+6) = 35(21)
21(3x+2) = 35(x+6)
63x + 42 = 35x + 210
28x = 168
x = 6
