Answer:
e44u75g hhd fgj jh hhff hhff gft8886
Answer:
(a) Gg × Gg; (b) genotypic = 1:2:1, phenotypic = 3:1
Explanation:
a) A cross between two gray seeded plants produces progeny with gray and white seeds in 3:1 ratio (302:98=3:1). This means that the parent plants are heterozygous and each has at least one recessive allele. If the allele "G" is responsible for gray seed and the allele "g" imparts white color to the seeds, the genotype of the heterozygous parents would be "Gg".
b) A cross between two heterozygous gray seeded parents would produce progeny in following ratio:
Genotype ratio= 1 GG: 2 Gg: 1 gg
Phenotype ratio= 3 Gray: 1 white
Answer:
16 possible combinations
Explanation:
Gamete formation involves the random and independent segregation of the alleles. During anaphase I (meiosis) occurs the independent separation of homologous chromosomes that migrate to opposite poles of the cell. This separation generates different chromosomal combinations in the daughter cells. There are two alternatives per homologous pair.
The number of gametes with different combinations is 2ⁿ, where
n = number of homologous pairs.
In the exposed example there are 4 pairs of chromosomes, so
the number of possible combinations of chromosomes = 2ⁿ = 2⁴ = 16