There are 3, Tubular, Clincher, and tubeless.
Answer:
I think it is 5.6. This is my answer
Answer:
I = 4.75 A
Explanation:
To find the current in the wire you use the following relation:
(1)
E: electric field E(t)=0.0004t2−0.0001t+0.0004
ρ: resistivity of the material = 2.75×10−8 ohm-meters
J: current density
The current density is also given by:
(2)
I: current
A: cross area of the wire = π(d/2)^2
d: diameter of the wire = 0.205 cm = 0.00205 m
You replace the equation (2) into the equation (1), and you solve for the current I:

Next, you replace for all variables:

hence, the current in the wire is 4.75A
Answer:
The Minimum wavelength is 
The Maximum wavelength is
Explanation:
From the question we are told that
The energy range is 
Considering 
When a single photon is transferred to to an electron the energy obtained can be calculated as follows

This energy is mathematically represented as

Here h is the Planck's constant with value of 
c is the speed of light with value of
Substituting values and making
the subject of the formula


Considering 
When a single photon is transferred to to an electron the energy obtained can be calculated as follows

This energy is mathematically represented as

Substituting values and making
the subject of the formula
