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Marizza181 [45]
3 years ago
12

Why can you hear a man's voice around the corner of a building even if you can't see him?

Physics
1 answer:
OverLord2011 [107]3 years ago
4 0

Answer:

Diffraction

Explanation:

the sound bounces off the corner and we are able to hear it

A P E X

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What is the formula for Charles Law?
Vlada [557]

Answer:

Explanation:

V_{1} = first volume

V_{2} = second volume

T_{1} = first temperature

T_{2} = second temperature

4 0
3 years ago
A rock with a mass of 10.0kg falls 25.0m to
Jlenok [28]

Answer:

man brainly should put a rank for having negative points

Explanation:

that would be me right now

8 0
3 years ago
Two equally charged, 2.807 g spheres are placed with 3.711 cm between their centers. When released, each begins to accelerate at
statuscvo [17]
\begin{gathered} m=\text{ 2.807 g} \\ d=\text{ 3.711cm} \\ a=260.125\text{ m/s}^2 \\ m=\text{ mass of  both the spheres} \\ d=\text{ distance between the centers of sphere.} \\ a=\text{ acceleration of spheres.} \end{gathered}\begin{gathered} force\text{ due to the sphere having charge q, outside its surface is given by } \\ \vec{F}=\frac{1}{4\pi\epsilon_o}\frac{q_1q_2}{r^2}\hat{r} \\ q_1=charge\text{ on the source object.} \\ q_2=charge\text{ of the object in which we are observing the force.} \\ F=\text{ the force on the charged particle outside the sphere} \\ r=\text{ distance of the charged particle from the center of the sphere} \\ \hat{r}\text{= direction of the force acting on the charged particle} \end{gathered}\begin{gathered} from\text{ Newton's second law} \\ F=ma \\ F=\text{ force acting on the particle.} \\ m=\text{ mass of the object.} \\ a=\text{ acceleration of the object.} \end{gathered}\begin{gathered} from\text{ both the equation } \\ ma=\frac{1}{4\pi\epsilon_o}\frac{q_1q_{\frac{2}{}}}{r^2}\hat{r} \\ here\text{ q}_1\text{ and q}_2\text{ are the same, according to the question.} \end{gathered}\begin{gathered} converting\text{ all the values in s.i. unit} \\ m=2.807*10^{-3}kg \\ d=3.711*10^{-2}m \\ according\text{ to the question q}_1=\text{ q}_2 \\ value\text{ of }\frac{1}{4\pi\epsilon_o}=9*10^9\text{ Nm}^2\text{/C}^2 \\ now\text{ put all the values in the above equation } \\ 2.807*10^{-3}kg*260.125\text{ m/s\textasciicircum2}=9*10^9Nm^2\text{/C}^2*\frac{q^2}{3.711*10^{-2}m} \\  \end{gathered}\begin{gathered} by\text{ trasformation} \\ q=\sqrt{\frac{2.807*10^{-3}kg*260.125m/s^2*3.711*^10^{-2}m}{9*10^9Nm^2\text{/C}^2}} \\ by\text{ solving this we get } \\ q=17.3514*10^{-7}C \\ q=1.73514\text{ micro coulombs.} \end{gathered}Hence the correct answer is q= 1.73514 micro coulombs.
5 0
1 year ago
Two trains move towards each other on a straight track/railroad. The left train has a constant speed of 29ms, the right train ha
laiz [17]

Answer:

The left train travels 2378 m until it reaches the meeting point.

Explanation:

The equation for the position of the trains is the following:

x = x0 + v · t

Where:

x = position at time t

x0 = initial position

v = velocity

t = time

If we place the origin of the frame of reference at the initial position of the left train, the right train will be at an initial position of 4744. 6 m relative to the left train. The velocity of the right train will be negative because it will be heading towards the origin.

At the meeting point, the position of both trains is the same:

x left train = x right train

x0₁ + v₁  ·t = x0₂ + v₂ · t

0m + 29 m/s · t = 4744.6 m - 29 m/s · t

58 m/s · t = 4744.6 m

t = 4744.6 m / 58 /s

t = 82 s

The position of the left train at that time will be:

x = x0 + v · t

x = 0 m + 29 m/s · 82 s

x = 2378 m

The left train travels 2378 m until it reaches the meeting point.

7 0
3 years ago
scientific endeavor is a purely positive action that does not sometimes cause potentially harmful results.
Naya [18.7K]
I think that the question is simply asking whether the statement is correct.

The statement is wrong! The scientific endeavor (the work of the scientists, the pursue of knowledge) can be potentially harmful. For example, many tests of human medicine have to be performed on animals, and often the medicine causes great suffering in the animals (and gets rejected for testing on humans).
6 0
3 years ago
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