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harina [27]
3 years ago
8

How do different factors affect solubility? Check all of the boxes that apply.

Physics
2 answers:
Karo-lina-s [1.5K]3 years ago
4 0

Answer:

Explanation:

Solubility is affected by current concentration, mechanical disturbance, temperature and pressure. So the answers are:

- Increasing temperature decreases the solubility of gases.

- Stirring increases the solubility of solids.

- Increasing pressure increases the solubility of gases.

- Decreasing the amount of solvent decreases the solubility of solids, liquids, and gases.

Alika [10]3 years ago
3 0

Answer:

Explanation:

Increasing temperature decreases the solubility of gases : true

Stirring increases the solubility of solids.: true

Increasing pressure increases the solubility of liquids : false

Decreasing temperature decreases the solubility of solids.: true

Increasing pressure increases the solubility of gases: true

Decreasing the amount of solvent decreases the solubility of solids, liquids, and gases : true

​

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MA_775_DIABLO [31]

it's a. open circuit

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3 years ago
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The ability of atoms to attract electrons is referred to as
dexar [7]

Answer: electronegativity

Explanation:

Electronegativity is defined as the property of an element to attract a shared pair of electron towards itself.  

The size of an atom decreases as we move across the period because the electrons get added to the same shell and the nuclear charge keeps on increasing. Thus the electrons get more tightly held by the nucleus.

As, the size of an element decreases, the valence electrons come near to the nucleus. So, the attraction between the nucleus and the shared pair of electrons increases and thus the electronegativity increases.

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4 years ago
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Two particles are fixed to an x axis: particle 1 of charge q1 = 2.78 × 10-8 c at x = 15.0 cm and particle 2 of charge q2 = -3.24
Oksi-84 [34.3K]
Refer to the attached figure. Xp may not be between the particles but the reasoning is the same nonetheless.
At xp the electric field is the sum of both electric fields, remember that at a coordinate x for a particle placed at x' we have the electric field of a point charge (all of this on the x-axis of course):
E=\frac{1}{4\pi\varepsilon_0}\frac{q}{(x-x')^2}
Now At xp we have:
\frac{1}{4\pi\varepsilon_0}\frac{q_1}{(x_p-x_1)^2}-\frac{1}{4\pi\varepsilon_0}\frac{3.29q_1}{(x_p-x_2)^2}=0
\implies (x_p-x_1)^2=\frac{(x_p-x_2)^2}{3.29}\\&#10;\implies(1-\frac{1}{3.29})x_p^2+2(\frac{x_2}{3.29}-x_1)x_p+x_1^2-\frac{x_2^2}{3.29}=0
Which is a second order equation, using the quadratic formula to solve for xp would give us:
xp=\frac{-(\frac{x_2}{3.29}-x_1)-\sqrt{(\frac{x_2}{3.29}-x_1)^2-(1-\frac{1}{3.29})(x_1^2-\frac{x_2^2}{3.29})}}{(1-\frac{1}{3.29})}
or
xp=\frac{-(\frac{x_2}{3.29}-x_1)+\sqrt{(\frac{x_2}{3.29}-x_1)^2-(1-\frac{1}{3.29})(x_1^2-\frac{x_2^2}{3.29})}}{(1-\frac{1}{3.29})}
Plug the relevant values to get both answers.
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Let's place a possitive test charge on the system This charge feels a repulsive force due to q1 but an attractive force due to q2, if we place the charge somewhere to the left of q2 the attractive force of q2 will cancel the repulsive force of q1, this translates to a zero electric field at this x coordinate. The same could happen if we place the test charge at some point to the right of q1, hence we can have two possible locations in which the electric field is zero. The second image shows two possible locations for xp.

6 0
4 years ago
When a 2.60-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.86 cm. (a) W
Goryan [66]

Answer:

a)  k = 891.82 N/m

b) e = 0.0143 m = 1.43 cm

c) W = 5.02 J

Explanation:

Step 1: Data given

Mass = 2.60 kg

the spring stretches 2.86 cm = 0.0286

Step 2: What is the force constant of the spring?

Force constant, k = force applied / extension produced  

k = (2.60kg * 9.81N/kg) / 0.0326 m

k = 891.82 N/m

b)  If the 2.60-kg object is removed, how far will the spring stretch if a 1.30-kg block is hung on it

Extension = F/k = (1.30 kg * 9.81) / 891.82 =  0.0143 m = 1.43 cm

Half the mass means half the extension

c) How much work must an external agent do to stretch the same spring 7.50 cm from its unstretched position?

W = average force used * distance

W = 1/2 * k*e * e = 1/2 k*e²  

W = 1/2 * 891.82 * (0.075)² = W = 5.02 J

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A man holds a child on his shoulders while watching a football match. How many work has he done if the game lasts for 2 hours? ​
Shalnov [3]

very interesting and amazing question u had asked but i get it...

Answer

  • work done is given by

W = Force × Displacement

  • but in above case force is exerted on the men as the weight of the child × gravitational pull of earth (9.8 m/s^2) but the displacement or movement is ZERO
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<u>More</u><u> </u><u>examples</u>

  • a person standing straight and lifting weight
  • a person carry some weight and walk in a circular path and came back to its original position.........in this case also Displacement will be zero

------------------------------------

hope it helped u buddy

4 0
4 years ago
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