Answer:
The answer is "Option A"
Explanation:
In the given java code, a class "Test" is defined, inside the main method try and catch block is used, inside the try block method "p()" is called, that print a message. in this block two catch block is used, that works on "NumberFormatException" and "RuntimeException". In the method "p" declaration, a string variable "s" is defined, that holds double value, that is "5.6", and converts its value into the wrong integer, and other wrong option can be described as follows:
- In option B, it is wrong, it is not followed by after call method.
- In option C, It is not followed by runtime exception, that's why it is incorrect.
- Option D and Option E both were wrong because they can't give run time and compile-time error.
Answer:
Colon(:) is the correct answer.
Explanation:
The colon(:) is used to contain those fields which is calculated in the queries. In other words, the colon is used to insert the name for that field which is calculated then, the user uses the colon(:) and after that, he uses the expression in the columns or the field row. So, That's why the following option is true.
Answer:
Because you could also receive shock
Explanation:
Automatic external defibrillators can help save lives during sudden cardiac arrest.
Do not touch the person while the AED is analyzing; touching or moving the person can affect the analysis. You or another person could be injured by shock. And you could prevent the AED from analyzing your heart rate correctly.
Answer:
- def normalize(input_string):
- output = []
-
- for c in input_string:
- if(c.isalpha()):
- output.append(c.lower())
-
- return output
-
- print(normalize("O.K. #1 Python!"))
Explanation:
Firstly, create a function normalize that takes one input string (Line 1).
Next, we create an empty list and assign it to output variable (Line 2). This list will hold all the letters from the input string.
Create a for loop to traverse each of the character in the input string (Line 4) and then use isalpha() method to check if the current character is a letter (Line 5). If so, add the letter to output list (Line 6). Please note we can convert the letter to lowercase using lower() method.
After completing the loop, return the output list (Line 8).
We can test the function using the sample input given in the question (Line 10) and we shall get ['o', 'k', 'p', 'y', 't', 'h', 'o', 'n']
