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ss7ja [257]
3 years ago
5

The volume of a cube depends on the length of its sides. This can be written in function notation as v(s). What is the best inte

rpretation of v(2) = 8?
A. A cube with a volume of 2 cubic feet has side lengths of 8 feet.
B. 2 of these cubes will have a total volume of 8 cubic feet.
C. 2 sides of the cube have a total length of 8 feet.
D. A cube with side lengths of 2 feet has a volume of 8 cubic feet.
Mathematics
1 answer:
ki77a [65]3 years ago
7 0
The answer is D. A cube with side lengths of 2 feet has a volume of 8 cubic feet.
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Which region labeled in the graph below would represent the solution (the final shaded area) to the system of linear inequalitie
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Answer:

Region D.

Step-by-step explanation:

Here we have two inequalities:

y ≤ 1/2x − 3

y < −2/3x + 1

First, we can see that the first inequality has a positive slope and the symbol (≤) so the values of the line itself are solutions, this line is the solid line in the graph.

And we have that:

y ≤ 1/2x − 3

y must be smaller or equal than the solid line, so here we look at the regions below the solid line, which are region D and region C.

Now let's look at the other one:

y < −2/3x + 1

y = (-2/3)*x + 1

is the dashed line in the graph.

And we have:

y < −2/3x + 1

So y is smaller than the values of the line, so we need to look at the region that is below de dashed line.

The regions below the dashed line are region A and region D.

The solution for the system:

y ≤ 1/2x − 3

y < −2/3x + 1

Is the region that is a solution for both inequalities, we can see that the only region that is a solution for both of them is region D.

Then the correct option is region D.

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Answer:

D: The function has a hole when x = 3, and vertical asymptotes when x = 0 and x = 5.

Step-by-step explanation:

The given rational function has vertical asymptotes and holes. Remember that an asymptote is placed when the function has undetermined results, when we give a x-value and the y-value cannot be determined, there we say exists an asymptotes, which is a punctual line that represents a discontinuation of the graph, the trace cannot cross that asymptote, it divide the whole function graph.

So, in this case we have to undetermined results when the function has a hole of x = 3, and vertical asymptotes when x = 0 and x = 5.

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