Answer:
41.3 s
Explanation:
Let t₁ represent the time taken for SO₂ to effuse.
Let t₂ represent the time taken for Ar to effuse.
Let M₁ represent the molar mass of SO₂
Let M₂ represent the molar mass of Ar
From the question given above,
Time taken (t₁) for SO₂ = 52.3 s
Time taken (t₂) for Ar =?
Molar mass (M₁) of SO₂ = 32 + (16×2) = 32 + 32 = 64 g/mol
Molar mass (M₂) of Ar = 40 g/mol
Finally, we shall determine the time taken for Ar to effuse by using the Graham's law equation as shown below:
t₂ / t₁ = √(M₂ / M₁)
t₂ / 52.3 = √(40 / 64)
t₂ / 52.3 = √0.625
t₂ / 52.3 = 0.79
Cross multiply
t₂ = 52.3 × 0.79
t₂ = 41.3 s
Thus, the time taken for the amount of Ar to effuse is 41.3 s
I would say is because of the Boron from O?
Attraction between polar molecules
Phosphorus is in group 15 meaning it have 5 valence electrons. This means that it needs 3 more electrons to create a full outer shell. As these three electrons are negatively charged it means that P is a 3- ion (it’s an anion [negatively charged ion])
