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Ierofanga [76]
3 years ago
10

Suppose you are shooting a basketball toward a hoop. As the ball rises in the air, its ---------------- energy increases and its

---------------------------- decreases.
Chemistry
2 answers:
Anna11 [10]3 years ago
7 0

Answer:

Suppose you are shooting a basketball toward a hoop. As the ball rises in the air, its -------Potential --------- energy increases and its -----------kinetic----------------- decreases.

Explanation:

Kinetic energy is the energy of movement or change. Potential energy is the energy a system has as a result of being able to undergo some change. ... As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy.

faust18 [17]3 years ago
3 0
Kinetic//the movement energy
potential//energy by position
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It is separated by The particles that are removed from the water by the filter are called the residue. Another common separation process is called distillation. Distillation uses boiling to separate mixtures of liquid solutions. It takes into account that different substances in the mixture will have different boiling points.
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During a reaction, the enthalpy of formation of an intermediate is 34 kJ/mol.
galina1969 [7]

Since the enthalpy can be calculated from the heat of formation, the enthalpy is 136 kJ/mol.

<h3>What is enthalpy?</h3>

The enthalpy of a reaction is the heat that is lost or gained in that reaction. We know that the enthalpy can be calculated from the heat of  formation.

Thus, we can obtain the enthalpy of the reaction as 4 * 34 kJ/mol = 136 kJ/mol.

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5 0
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ser-zykov [4K]

Explanation:

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6 0
3 years ago
On the reaction below, label the BSA, BSB, CA, and CB. CH3COOH + H2O → CH3COO– + H3O+
Ostrovityanka [42]

Answer:

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Base (BSB) = H₂O

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Explanation:

Equation of reaction;

CH₃COOH + H₂O → CH₃COO⁻ + H₃O⁺

Hello,

From my understanding of the question, we are required to identify the

1) Acid

2) Base

3) conjugate acid

4) conjugate base in the reaction

Acid (BSA) = CH₃COOH

Base (BSB) = H₂O

CA = conjugate acid = H₃O⁺

CB = conjugate base = CH₃COO⁻

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Evgesh-ka [11]
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