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Ronch [10]
3 years ago
14

Solutions of hydrochloric acid caused the light bulb to glow brighter than solutions of acetic acid. how do you account for the

difference in behavior between these two compounds?
Chemistry
1 answer:
maksim [4K]3 years ago
7 0
<span>The primary difference between hydrochloric acid and acetic acid is that hydrochloric acid undergoes a complete ionization, whereas acetic acid does not. This is why a light bulb will burn brighter in the solutions of hydrochloric acid, and also why hydrochloric acid is considered a strong acid, while acetic acid is considered a weak acid.</span>
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Use a sheet of paper to answer the following question. Take a picture of your answers and attach to this assignment. Draw the st
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Answer:

Explanation:

Structure of the 2,2,4,4-tetramethyl-3-pentanone is give in the attachment

In 2,2,4,4-tetramethyl-3-pentanone, no alpha hydrogen is present, therefore, enol form is not possible and hence, exist only in keto form.

Explanation for existence of cyclohexa-2,4-diene-1-one only in enol form:

keto form of cyclohexa-2,4-diene-1-one not aromatic and hence less stable.

Whereas enol form it is aromatic which makes it highly stable. that's why cyclohexa-2,4-diene-1-one exists only in enol form.

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Sergeeva-Olga [200]

Answer:

The empirical formula is SF6 (option E)

Explanation:

Step 1: Data given

Mass of sulfur = 3.21 grams

Mass of fluorine = 11.4 grams

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Step 2: Calculate moles

Moles = mass /molar mass

Moles sulfur = 3.21 grams / 32.065 g/mol

Moles sulfur = 0.100 moles

Moles fluorine = 11.4 grams / 19.00 g/mol

Moles fluorine = 0.600 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

S: 0.100 / 0.100 = 1

F : 0.600 / 0.100 = 6

The empirical formula is SF6 (option E)

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3 years ago
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The answer is C

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Sodium ions and sulfate ions shall be present in the solution.

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