The interquartile range is 5!
Lol
The answer to this should be a-8b+13c
a - {4b - [a - (5b - c) + 3c - (a - b - 9c)]}
=a - {4b - [a - 5b + c + 3c - a + b + 9c]}
=a - {4b - [- 4b+ 13c]}
=a - {4b + 4b -13c}
=a - 8b + 13c
Hope this helped :)
Have a great day
Neither. When graphing both lines they intersect but are not perpendicular.
Answer:x= 2b/e -c
Step-by-step explanation:
<h3>
Answers:</h3>
Variation Constant: k = 7/6
y = 245/6 when x = 7 and z = 5
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Explanation:
"y varies jointly as x and z" means that y = kxz
We have (x,y,z) = (4,14,3) as one triple, so,
y = kxz
14 = k*4*3
14 = 12k
12k = 14
k = 14/12
k = 7/6 is the variation constant
The equation goes from y = kxz to y = (7/6)xz
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Plug in x = 7 and z = 5 to find y
y = (7/6)xz
y = (7/6)*7*5
y = (7/6)*(7/1)*(5/1)
y = (7*7*5)/(6*1*1)
y = 245/6
