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3 years ago

The difference of a number and -6 is less than 9 write an inequality and solve

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

8 0

Answer:

n - (-6) < 9

n < 3

Step-by-step explanation:

When setting up an inequality, using the key words from the problem will help. The word 'difference' would indicate subtraction and 'less than' would be the '<' inequality sign. Since the expression is 'the difference of a number and -6', we write:

n - (-6) < 9

Whenever we subtract a negative number, we change both signs to positive:

n + 6 < 9

Using inverse operations to solve: n + 6 - 6 < 9 - 6

n < 3

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A-2=-1 + 2a-4-1 send me the work please! (solving equations with variables on both sides)

Vladimir [108]

The value of "a" is 4

Solution:

Given expression is:

$a - 2 = -1 + 2a - 4-1$

The above expression involves variables and constants

A variable is a symbol that represents an unknown number

Here the variable is "a"

Constants are fixed numbers like 1, 2 etc

From given expression:

$a - 2 = -1 + 2a - 4-1$

Move the varibale "2a" from right side to left side of equation

When, 2a is moved from R.H.S to L.H.S, it becomes -2a

$a -2a - 2 = -1 -4-1$

Now move the constant -2 from left side to right side of equation

Similarly, when -2 is moved from L.H.S to R.H.S, it becomes +2

$a-2a = -1-4-1+2$

Now add the variables on left side of equation

$-a = -1-4-1+2$

Now add the constants on right side of equation

$-a = -6+2\\\\-a = -4$

Cancel the negative sign on both sides of equation

$a=4$

Thus the value of "a" is 4

6 0

3 years ago

Let f be a functions of degree 4 whose coefficients are real numbers: two of its zeros are - 3 and 4 - i. Explain why one of the

kvasek [131]

Answer:

Step-by-step explanation:

We have the following theorem, if f is a polynomial with real coefficients, we can factor it completely in factors of the degree at most 2.

Consider first a polynomial of degree two, hence it is a polynomial of the form $ax^2+bx+c$ . The cuadratic formula tells us that the solutions are of the form

$x = \frac{-b\pm \sqrt[]{b^2-4ac}}{2a}$ .

Note that square root, over the reals, tells us that the are only real solutions if $b^2-4ac \geq 0$ . If that is not the case, say it's negative, the solution are complex. Then, the solutions are of the form

$x = \frac{-b \pm i \sqrt[]{4ac-b^2}}{2a}$ . NOte that this means that if we have a complex number of the form a+bi that is a solution, then the number a-bi (who is called the complex conjugate) is also a solution.

Recall that when we have a polynomial f(x) whose a zero is the number c, then we can factor f as follows f(x) = (x-c) * p(x) where p(x) is another polynomial of lesser degree .

So far, we know that -3 and 4-i are zeros of the function f. Note that we are missing two zeros. But, since complex numbers are zeros of polynomial only by pairs (that is the number and its conjugate are zeros), then, we must have that one of the missing 2 zeros is a real number. We have 4-i as a zero, then, its complex conjugate must be also a zero, i.e 4+i is a zero.

8 0

3 years ago

Help I have no clue how to do this

Leokris [45]

45 because 270 + 45 =315 . So 360-315= 45

5 0

3 years ago

The basement of a large department store features discounted merchandise. Their policy is to reduce the previous month's price o

Marizza181 [45]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
P(t) = Po(1 - r)^t

P(t) = price after t months --> S
Po = initial price -- P
r = rate as a decimal

S = P(.9)^4
-> = 100(.9)^4
-> = 65.61

(100 - 65.61)/100
34.39/100
34%

5 0

3 years ago

When the sum of twice a number and 4 is tripled the result is 72?

mafiozo [28]

The unknown value can be called x.
3(2x +4) = 72
6x +12 = 72
72 - 12 = 6x
6x = 60
x = 6x / 6
x = 10

Hope This Helps You!
Good Luck Studying :)

7 0

3 years ago