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3 years ago

Interest: $160.67 Principal: $2000 Rate: % Time: 8 months

Mathematics

1 answer:

ivanzaharov [21]3 years ago

4 0

Answer:

12.05%

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 12.050249999994%/100 = 0.12050249999994 per year,

then, solving our equation

I = 2000 × 0.12050249999994 × 0.666666666667 = 160.67

I = $ 160.67

The simple interest accumulated

on a principal of $ 2,000.00

at a rate of 12.050249999994% per year

for 0.666666666667 years is $ 160.67.

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2 2/3 of what number is 6 1/7

borishaifa [10]

$2\frac{2}{3}$ of $2\frac{17}{56}$ is $6\frac{1}{7}$

Solution:

Given $2\frac{2}{3}$ of what number is $6\frac{1}{7}$ .

Let us first convert the mixed fraction into improper fraction.

$$2\frac{2}{3}=\frac{(2\times3)+2}{3}=\frac{8}{3}$

$$6\frac{1}{7}=\frac{(6\times7)+1}{3}=\frac{43}{3}$

Now, let us take the unknown number be x.

$$2\frac{2}{3}\times x=6\frac{1}{7}$

$$\frac{8}{3}\times x=\frac{43}{7}$

Do the cross multiplication.

$$ x=\frac{43}{7}\times\frac{3}{8}$

$$ x=\frac{43\times3}{7\times8}$

$$ x=\frac{129}{56}$

Now, again change the improper fraction into mixed fraction.

$$ x=2\frac{17}{56}$

Hence $2\frac{2}{3}$ of $2\frac{17}{56}$ is $6\frac{1}{7}$ .

6 0

3 years ago

Samantha Vega's gross weekly salary is $600. Her weekly federal withholding is $35.00. The Social Security

dedylja [7]

Answer:

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Step-by-step explanation:

5 0

3 years ago

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What substitution should be used to rewrite 16(x3 + 1)2 – 22(x3 + 1) – 3 = 0 as a quadratic equation?

Vesna [10]

Answer:

z = x^3 +1

Step-by-step explanation:

Noting the squared term, it makes sense to substitute for that term:

z = x^3 +1

gives ...

16z^2 -22z -3 = 0 . . . . the quadratic you want

_____

<em>Solutions derived from that substitution</em>

Factoring gives ...

16z^2 -24z +2z -3 = 0

8z(2z -3) +1(2z -3) = 0

(8z +1)(2z -3) = 0

z = -1/8 or 3/2

Then we can find x:

x^3 +1 = -1/8

x^3 = -9/8 . . . . . subtract 1

x = (-1/2)∛9 . . . . . one of the real solutions

x^3 +1 = 3/2

x^3 = 1/2 = 4/8 . . . . . . subtract 1

x = (1/2)∛4 . . . . . . the other real solution

The complex solutions will be the two complex cube roots of -9/8 and the two complex cube roots of 1/2.

7 0

3 years ago

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A Geometric series has a first term of 4 and a common ratio of 6. what formula is equivalent to the partial sum of the first n t

IRISSAK [1]

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=6
\end{cases}
\\\\\\
S_n=4\left( \cfrac{1-6^n}{1-6} \right)\implies S_n=4\left( \cfrac{1-6^n}{-5} \right)$