Answer:
Reduction involves a half-reaction in which a chemical species decreases its oxidation number, usually by gaining electrons. The other half of the reaction involves oxidation, in which electrons are lost. Together, reduction and oxidation form redox reactions (reduction-oxidation = redox).
Explanation:
Hope this helps :)
<u>Answer:</u> The final temperature of the system is 14.60°C
<u>Explanation:</u>
When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

The equation used to calculate heat released or absorbed follows:

......(1)
where,
q = heat absorbed or released
= mass of aluminium = 25.00 g
= mass of water = 100 g
= final temperature = ?°C
= initial temperature of aluminium = 100°C
= initial temperature of water = 10°C
= specific heat of aluminium = 0.900 J/g°C
= specific heat of water= 4.18 J/g°C
Putting values in equation 1, we get:
![25\times 0.900\times (T_{final}-100)=-[100\times 4.18\times (T_{final}-10)]](https://tex.z-dn.net/?f=25%5Ctimes%200.900%5Ctimes%20%28T_%7Bfinal%7D-100%29%3D-%5B100%5Ctimes%204.18%5Ctimes%20%28T_%7Bfinal%7D-10%29%5D)

Hence, the final temperature of the system is 14.60°C
<u><em>Answer:</em></u>
<u><em>Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. Since the particles in a liquid are tightly packed, this pressure acts in all directions. For example, the pressure acting on a dam at the bottom of a reservoir is greater than the pressure acting near the top.</em></u>
<u><em>Explanation:</em></u>
<u><em></em></u>
Answer:
Q = 5254.39 J
Explanation:
Given that,
Mass of ethanol, m = 68.8 g
The temperature increases from 40.0°C to 71.3°C.
The specific heat of ethanol is 2.44 j/g°C
We need to find the heat absorbed by the ethanol. We know that the heat absorbed due to the change in temperature is given by :

Put all the values,

So, 5254.39 J of heat is absorbed by Ethanol.
Answer:
1 mole.
Explanation:
1.6x10^23 = NA = 1 mole of any substance.