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2 years ago

Please please !!! help me I’ve been doing this for 2 hours

Chemistry

1 answer:

MatroZZZ [7]2 years ago

6 0

Answer:

3.7 x 10^23

is the right answer

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Determine the empirical formula of a compound that contains 30.45% nitrogen and 69.55% oxygen

melomori [17]

I might not be right but I think the empirical formula is NO2

5 0

2 years ago

Calculate the mass of magnesium carbonate ( MgCO3), in grams, required to produce 110.0 g of carbon dioxide using the following

bearhunter [10]

Answer:

$210.7~g~MgCO_3$

Explanation:

We have to start with the reaction:

$MgCO_3~->~MgO~+~CO_2$

We have the same amount of atoms on both sides, so, we can continue. The next step is to find the number of moles that we have in the 110.0 g of carbon dioxide, to this, we have to know the atomic mass of each atom:

C: 12 g/mol

O: 16 g/mol

Mg: 23.3 g/mol

If we take into account the number of atoms in the formula, we can calculate the molar mass of carbon dioxide:

$(12*1)+(16*2)=44~g/mol$

In other words: $1~mol~CO_2=~44~g~CO_2$ . With this in mind, we can calculate the moles:

$110~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=25~mol~CO_2$

Now, the molar ratio between carbon dioxide and magnesium carbonate is 1:1, so:

$2.5~mol~CO_2=2.5~mol~MgCO_3$

With the molar mass of $MgCO_3$ ( $(23.3*1)+(12*1)+(16*3)=84.3~g/mol$ . With this in mind, we can calculate the grams of magnesium carbonate:

$2.5~mol~MgCO_3\frac{84.3~g~MgCO_3}{1~mol~MgCO_3}=210.7~g~MgCO_3$

I hope it helps!

8 0

2 years ago

Find the molar mass of this

kirill115 [55]

Explanation:

Given problem:

Find the molar mass of:

SO₃ and C₁₀H₈

Solution:

The molar mass of a compound is the mass in grams of one mole of the substance.

To solve this, we are going to add the individual atomic masses of the elements in the compound;

Atomic mass;

S = 32g/mol; O = 16g/mol; C = 12g/mol and H = 1g/mol

For SO₃;

= 32 + 3(16)

= 32 + 48

= 80g/mol

For C₁₀H₈

= 10(12) + 8(1)

= 120 + 8

= 128g/mol

7 0

2 years ago

aspirin C6H4(CO2)(CO2CH3),can be prepared in the chemistry laboratory by the reactions of salicylic acid, C6H4(CO2H)(OH),with ac

Ket [755]

262mol 1=kg
g=1000
from stoichoimetry

x=102*1000/360
x=102000/360
x=283.33

density =m/v
=283.33/1.082
=262mol

8 0

3 years ago

For a half-reaction in an acidic solution, which substances should you add to balance the equation?

solmaris [256]

Hello!

I believe the correct answer to this question is H+ and H2O.

I hope you found this helpful! :)

8 0

3 years ago