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3 years ago

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If 0.55 g of a gas dissolved in 1.0 l of water at 20.0 kpa of pressure, how much will dissolve at 110.0 kPa of pressure?

1 answer:

GaryK [48]3 years ago

4 0

Answer:sup

Explanation:

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Identify the mixture of gasoline and motor oil and suggest a technique for separating their components. 1. homogeneous; decantin

alexgriva [62]

Answer:

4. homogeneous; distillation

Explanation:

Gasoline and motor oil are chemically similar. They are both mixtures of non polar hydrocarbons containing carbon and hydrogen atoms. However, motor oil is much more viscous Motor Oil. Hence we can say that the mixture of gasoline and motor oil are homogeneous and they can be separated by distillation.

4 0

3 years ago

Read 2 more answers

A scuba diver is using scuba gear to breathe under water. The pressure on her lungs is 2.5 atm and her lung volume is 4.4 L. Wha

nikdorinn [45]

Answer:

<h2>2.44 L</h2>

Explanation:

The volume can be used by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2 \\$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the final volume

$V_2 = \frac{P_1V_1}{P_2} \\$

We have

$V_2 = \frac{2.5 \times 4.4}{4.5} = \frac{11}{4.5} \\ = 2.444444....$

We have the final answer as

<h3>2.44 L</h3>

Hope this helps you

3 0

3 years ago

Pb(NO3)2 + K2CO3 --> PbCO3 + KNO3<br> A. 5<br> B. 2<br> C.<br> 4

emmasim [6.3K]

Answer:

Pb(NO3)2 + K2CO3 ----> PbCO3 + 2KNO3

The answer is B. 2

Hope this helps!

4 0

3 years ago

What is the value for the reaction: N2(g) + 2 O2(g) --> N2O4(g) in terms of K values from the reactions:

Valentin [98]

Answer : The correct expression will be:

$K=(K_1)^2\times K_2$

Explanation :

The chemical reactions are :

(1) $\frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)\rightleftharpoons NO(g)$ $K_1$

(2) $2NO(g)+O_2(g)\rightleftharpoons N_2O_4(g)$ $K_2$

The final chemical reaction is :

$N_2(g)+2O_2(g)\rightleftharpoons N_2O_4$ $K=?$

Now we have to calculate the value of $K$ for the final reaction.

Now equation 1 is multiply by 2 and then add both the reaction we get the value of 'K'.

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

If the two equations are added then equilibrium constant will be multiplied.

Thus, the value of 'K' will be:

$K=(K_1)^2\times K_2$

6 0

3 years ago

How many electrons are there in the following compound?

Marina86 [1]

Answer:

look it up in google it dead in your face m8 i just did

Explanation:

4 0

3 years ago