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Allushta [10]
3 years ago
6

Write the numbers in scientific notation.

Chemistry
1 answer:
LenKa [72]3 years ago
7 0
2.917 x 10^2 0.960x 10^1
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The enthalpy change for converting 10.0 g of ice at -25.0 °C to water at 90.0 °C is __________ kJ. The specific heats of ice, wa
Nina [5.8K]
AH1 = m * c1 * AT1 calculate this for ice (-25C to 0C) AH2 = AHfus(1 mole)=6.01 kJ = 6010 J AH3 = m *c3 * AT3 calculat this for water (0C to 100C) AH4 = AHvap(1mole)=40.67 kJ = 40670 J AH5= m * c5 * AT5 calculate this for steam (100C to 125C) 
Sum ---- AH1+AH2+AH3+AH4+AH5 
Data m=18g (1mole water) 
c1=specific heat ice= 2.09 J/g K c3=specific heat water= 4.18 J/g K c5=specific heat steam= 1.84 J/g K 
AT = (Tend - Tinitial) as this is a difference between temperatures it doesn't matter the units Celsius or Kelvin. Kelvin (K)=Celsius (C)+273.15 
AT1 = 0C - (-25C)= 25C= 273.15K - 248.15K= 25K AT3= 100C - 0C = 100C= 100K AT5= 125C - 100C= 25C=25K
6 0
3 years ago
A mixture of CuSO4 · 5H2O and MgSO4 · 7H2O is heated until all the water is lost. If 5.127 g of the mixture gives 2.817 g of the
Nadusha1986 [10]

Answer:

Let the mixture is X% by mass of CuSO

4

.5H

2

O and 100 - X % by mass of MgSO

4

.7H

2

O. 5.0 g of mixture will contain 0.05X g CuSO

4

.5H

2

O and 5.0 - 0.05X g MgSO

4

.7H

2

O

The molar masses of CuSO

4

.5H

2

O and MgSO

4

.7H

2

O are 249.7 g/mol and 246.5 g/mol respectively.

The number of moles of CuSO

4

.5H

2

O=

249.7

0.05X

=2.00×10

−4

X moles.

Explanation:

Pls mark it as branliest answere thanks

3 0
2 years ago
Are metallic bonds are found in compounds
Ratling [72]

Answer:

Explanation:

Yes :)

Mark brainliest please

5 0
3 years ago
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Lucy wants to attach a goal cost to each of her life goals. Why might she do this?
Natasha2012 [34]

Answer:

So she can have something to reach or look forward to.

Explanation:

none

8 0
3 years ago
You pre-weigh a glass vial to hold your sample and find its mass to be 5.010 g. You add your sample to the vial and reweigh it o
san4es73 [151]
Answer : 1.12 grams

Yo find the mass of the sample, you take the increased mass and subtract the original mass.

6.130 - 5.010 = 1.12
8 0
2 years ago
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