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3 years ago

PLZZ HELP

Mathematics

2 answers:

Elan Coil [88]3 years ago

5 0

It is a function. This is because the x's don't repeat.

kifflom [539]3 years ago

4 0

This indeed is both a relation and a function because it is a set of ordered pairs and the x-axis does not repeat itself.

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If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2

kramer

Answer:

Step-by-step explanation:

Here it's given that ,

$\sf\red{\longrightarrow} A=\sqrt{s(s-a)(s-b)(s-c)}$

Also ,

$\sf\red{\longrightarrow} s =\dfrac{a+b+c}{2}$

And we need to find out the value of A , when

a = 3
b = 4
c = 5

So , on substituting the respective values to find s we have ,

$\sf\red{\longrightarrow} s =\dfrac{3+4+5}{2}=\dfrac{12}{2}=\bf{6}$

Now let's find out A as ,

$\sf\red{\longrightarrow} A = \sqrt{6(6-3)(6-4)(6-5)} \\$

$\sf\red{\longrightarrow}A =\sqrt{6 * 3 * 2 * 1}\\$

$\sf\red{\longrightarrow} A = \sqrt{3^2 * 2^2 *1^2}\\$

$\sf\red{\longrightarrow}A = 3*2\\$

$\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}$

7 0

2 years ago

There is a vendor at a carnival selling bags of cotton candy. Each bag of cotton candy has the same cost. She starts each day wi

umka21 [38]

Answer:

The cost of each cotton candy bag is $4.

Step-by-step explanation:

Consider the provided information.

Let, the vendor has $x$ dollar at the starting of each day.

Let, the cost of each cotton candy bag is $y$ .

Now when she sells a total of 12 bags, she has $128.

$x+12y=128$ .....(1)

After she sells a total of 20 bags, she has $160.

$x+20y=160$ ....(2)

Subtract equation 1 from equation 2.

$(x+20y)-(x+12y)=160-128$

$8y=32$

$y=4$

Hence, the cost of each cotton candy bag is $4.

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