20 = 2 x 2 x 5
15 = 3 x 5
common divisor (CD) of 20 and 15 is 5 so n should be 5 and each group has 4 boys and 3 girls.
If there are more than one CD, then there are more than one answer.
If they ask for the largest number of groups, greatest common divisor (GCD) will be the answer.
713/9
79 2/9 Decimal form: 79.222
713 divided by 9 is 79 with a quotient estimate of 2.
79 r 2
Answer:
yeah
Step-by-step explanation:
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Y equals nine x minus five I’m sorry I don’t know if I did the right thing but yeah
