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oksano4ka [1.4K]
3 years ago
11

superstore and cheap store are two supermarkets that sell boxes of the same type of cereal each supermarket has a special offer

which box of cereal is better for the value of money cheap store 600g 20% of the normal price of £5 superstore 600g + 30% extra £5
Mathematics
1 answer:
Lena [83]3 years ago
8 0

Answer:

Step-by-step explanation:

Cheapstore:

500p÷10=50p×2=100p or £1  

£4=600g

Superstore:

600g÷10=60g×3=180g+600g

£5=780g

600÷4=150g per pound

780÷5=156g per pound

The box from Superstore is best value

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If a solid cube has a density of 6.3 grams per millimeter and a volume of 30 millimeters, how much is it's mass?
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urn I contains 1 red chip and 2 white chips; urn II contains 2 red chipsand 1 white chip. One chip is drawn at random from urn I
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Answer:

Following are the answer to this question:

Step-by-step explanation:

In the question first calls the W if the transmitted chip was white so, the W' transmitted the chip is red or R if the red chip is picked by the urn II.  

whenever a red chip is chosen from urn II, then the probability to transmitters the chip in white is:  

P(\frac{w}{R}) = \frac{P(W\cap R)}{P(R)}  \ \ \ \ \ _{Where}\\\\P(R) = P(W\cap R) + P(W'\cap R) \\

The probability that only the transmitted chip is white is therefore P(W) = \frac{2}{3}\\, since urn, I comprise 3 chips and 2 chips are white.

But if the chip is white so, it is possible that urn II has 4 chips and 2 of them will be red since urn II and 2 are now visible, and it is possible to be: P(\frac{R}{W}) = \frac{2}{3}

P(W\cap R) = P(W) \times P(\frac{R}{W}) \\

                = \frac{2}{3}\times \frac{2}{4} \\\\= \frac{2}{3}\times \frac{1}{2} \\\\= \frac{2}{3}\times \frac{1}{1} \\\\=\frac{1}{3}\\\\= 0.333

Likewise, the chip transmitted is presumably red (P(W')= \frac{1}{3})and the chip transferred is a red chip of urn II (P(\frac{R}{W'})= \frac{3}{4}, and a red chip is likely to be red (\frac{R}{W'}).  

Finally, P(W'\cap R) = P(W') \times P(\frac{R}{W'})\\

                              = \frac{1}{3} \times \frac{3}{4} \\\\ = \frac{1}{1} \times \frac{1}{4} \\\\=\frac{1}{4}\\\\= 0.25

The estimation of P(R) and P(\frac{W }{R}) as:  

P(R) = 0.3333 + 0.25\\\\  \ \ \ \ \ \ \ \ \ = 0.5833 \\\\ P(\frac{W}{R}) = \frac{0.3333}{0.5833} \\\\\ \ \ \ \ \ \ = 0.5714

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