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2 years ago

8

true or false in deductive thinking you start with a given set of rules and conditions and determine what must be true as a cons

equence

2 answers:

egoroff_w [7]2 years ago

4 0

Pretty sure this is true.

soldier1979 [14.2K]2 years ago

3 0

The answer for your question is true.

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1. The dimensions of Mr. Bell's living room are 10 feet x 8 feet x 2 feet, and the dimensions of his kitchen are 20 feet x 2 fee

romanna [79]

Answer:

more detail

Step-by-step explanation:

8 0

3 years ago

Please help with my geometry!!!!

dlinn [17]

I wish i remembered that but it has been a while

3 0

2 years ago

Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor

GarryVolchara [31]

Answer:

$\mu_p -\sigma_p = 0.74-0.0219=0.718$

$\mu_p +\sigma_p = 0.74+0.0219=0.762$

68% of the rates are expected to be betwen 0.718 and 0.762

$\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696$

$\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784$

95% of the rates are expected to be betwen 0.696 and 0.784

$\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674$

$\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806$

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

$p \sim N(p, \sqrt{\frac{p(1-p)}{n}})$

So then:

$\mu_p = 0.74$

$\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219$

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

$\mu_p -\sigma_p = 0.74-0.0219=0.718$

$\mu_p +\sigma_p = 0.74+0.0219=0.762$

68% of the rates are expected to be betwen 0.718 and 0.762

$\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696$

$\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784$

95% of the rates are expected to be betwen 0.696 and 0.784

$\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674$

$\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806$

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0

3 years ago

The area of a rectangular wall of a barn is 75 75 square feet. its length is 10 10 feet longer than the width. find the length a

ziro4ka [17]

A = L * W
A = 75
L = W + 10

75 = W(W + 10)
75 = W^2 + 10W
W^2 + 10W - 75 = 0
(W + 15)(W - 5) = 0

W + 15 = 0
W = -15...not this one because it is negative

W - 5 = 0
W = 5 <=== width is 5 ft

L = W + 10
L = 5 + 10
L = 15 <=== length is 15 ft

6 0

3 years ago

Sodium-24 has a half-life of 15 hours. how many grams of a 900 g sample will remain after 90 hours

raketka [301]

Answer: Option 'B' is correct.

Step-by-step explanation:

Let the initial concentration be

$N_0=900\ g$

Let concentration after t= 90 hours be N

Since we have given that Sodium-24 has a half life of 15 hours i.e.

$t_{\frac{1}{2}}=15$

So, According to question,

$\text{ Number of half lives }=\frac{t}{t_{\frac{1}{2}}}\\\\\text{ Number of half lives }=\frac{90}{15}\\\\\text{ Number of half lives }=6$

As we know that

$\frac{N}{N_0}=(\frac{1}{2})^n\\\\N=N_0\times (\frac{1}{2})^n\\\\N=900\times (\frac{1}{2})^6\\\\N=\frac{900}{64}\\\\N=14.0625\ g$

Hence, Option 'B' is correct.

4 0

3 years ago