Let x be the length of the train.
On the basis of the observer;
Speed of the train = x/6
On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20
Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.
Therefore,
Length of train = 150 m
Speed of train = 25 m/s
Answer:
13 C
Step-by-step explanation:
15-2=13
Answer:
5 and 11
Step-by-step explanation:
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Answer:
2/3 = a/b
Step-by-step explanation:
6/9 = a/b
2/3 = a/b
Answer: 17.59 cm
Step-by-step explanation: C=2πr=2·π·2.8=17.59292 cm
