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salantis [7]
2 years ago
15

Look at the picture please!!!

Physics
2 answers:
postnew [5]2 years ago
7 0

Answer:

I think it is the 3 option

kakasveta [241]2 years ago
6 0

Answer:I think its c option 3 he is trying to protect jessica from possible over-exposure to x ray radiation

Explanation:

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In 2.5 S, a Car increases its speed from 20.0m/s to 25.0 m/s what is the acceleration of the car​
Dima020 [189]

Answer:

2 m/s

Explanation:

3 0
3 years ago
An elevator car has a mass of 750 kg, and its three passengers have a combined mass of 135 kg. If the elevator and its passenger
joja [24]

Answer:

The change in gravitational potential energy is -1.80x10⁵ J.

Explanation:

The change in gravitational potential energy is given by:

\Delta E_{p} = E_{p_{f}} - E_{p_{i}}

\Delta E_{p} = mgh_{f} - mgh_{i}

Where:

"i" is for final and "f" for final

m: is the mass

g: is the gravity = 9.81 m/s²

h: is the height

For the car and the passengers we have:

\Delta E_{p} = m_{T}g(h_{f} - h_{i}) = (750 kg + 135 kg)9.81 m/s^{2}(0 - 20.7 m) = -1.80 \cdot 10^{5} J      

The minus sign is because when the elevator car and the passengers are up they have a bigger gravitational potential energy than when they are in the ground.

Therefore, the change in gravitational potential energy is -1.80x10⁵ J.

I hope it helps you!                                                

3 0
3 years ago
Need help due in 4 minutes
sergey [27]

Answer:

speed

Explanation:

3 0
3 years ago
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A deep space probe travels in a straight line at a constant speed of over 16,000 m/s. Assuming there is no friction in space, if
77julia77 [94]
C because when the part gets out of the probe it would no longer stay contacted
6 0
3 years ago
What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a
viktelen [127]

Complete Question

A certain refrigerator, operating between temperatures of -8.00°C and +23.2°C, can be approximated as a Carnot refrigerator.

What is the refrigerator's coefficient of performance? COP

(b) What If? What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump? COP

Answer:

a

 COP = 8.49

b

  COP_1 = 9.49  

Explanation:

From the question we are told that

     The lower operation temperature of refrigerator is  T_1 =  -8.00^oC =  265 \  K

     The upper operation temperature of the refrigerator is   T_2 =  23.2 ^oC =  296.2 \  K

Generally the refrigerators coefficient of performance is mathematically represented as

        COP =  \frac{T_1}{T_2 - T_1  }

=>     COP =  \frac{265}{296.2 - 265  }

=>     COP = 8.49

Generally if a refrigerator (operating between the same temperatures) was instead used as a heat pump , the coefficient of performance is mathematically represented as

            COP_1 =  \frac{T_2}{ T_2 - T_1}  

=>         COP_1 =  \frac{296.2}{ 296.2 - 265 }  

=>         COP_1 = 9.49  

8 0
3 years ago
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