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Ira Lisetskai [31]
3 years ago
7

The volume flow rate of blood leaving the heart to circulate throughout the body is about 5 L/min for a person at rest. All this

blood eventually must pass through the smallest of blood vessels, the capillaries. A typical capillary is 6 μm (micrometer) in diameter, 1 mm long, and the blood flows through it at an average speed of 1 mm/s.a. Estimate the total number of capillaries in the body. b. Estimate the total surface area of all the capillaries. (hint: the surface area of one capillary is A = circumference x length).
Physics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

n=2.9\times 10^9

A=1.88\times 10^{-8}\ m^2

Explanation:

Given that

Q= 5 L/min

1 L = 10⁻³ m³/s

1 min = 60 s

Q=0.083 x 10⁻³ m³/s

d= 6 μm

v= 1 mm/s

So the discharge flow through one tube

q = A v

A=\dfrac{\pi}{4}d^2

A=\dfrac{\pi}{4}\times (6\times 10^{-6})^2\ m^2

A=2.8 x 10⁻¹¹ m²

v= 1 x 10⁻³  m/s

q= 2.8 x 10⁻¹⁴  m³/s

Lets take total number of tube is n

Q= n q

n=Q/q

n=\dfrac{0.083\times 10^{-3} }{ 2.8\times 10^{-14}}

n=2.9\times 10^9

Surface  area A

A= π d L

A=\pi \times 6\times 10^{-6}\times 10^{-3}\ m^2

A=1.88\times 10^{-8}\ m^2

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If the coefficient of kinetic friction between a 22 kg kg crate and the floor is 0.27, what horizontal force is required to move
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Answer:

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Explanation:

the data we have is:

mass: m=22kg

coefficient of friction: \mu =0.27

and we also know the acceleration of gravity is g=9.81m/s^2

We need to do an analysis of horizontal and vertical forces acting on the object:

-------

Vertically the forces acting on the object:

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  • weight: w=mg (acting down from)

so the sum of forces in the vertical axis "y" are:

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from Newton's second Law we know that F=ma, so:

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and since the object is not accelerating in the vertical direction (the movement is only horizontal) a_{y}=0, and:

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-----------

now let's analyze the horizontal forces

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and the two forces just mentioned must be opposite, thus the sum of forces in the "x" axis is:

F=ma_{x}=F-f\\ma_{x}=F-\mu mg

and we are told that the crate moves at a steady speed, thus there is no acceleration: a_{x}=0

and we get:

0=F-\mu mg\\F=\mu mg

substituting known values:

F=(0.27)(22kg)(9.81m/s^2)\\F=58.27N

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3 years ago
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