Question

The turnover number is defined as the maximum number of substrate molecules that can be converted into product molecules per unit time by an enzyme molecule. The concentration of enzyme active sites is not necessarily equal to the concentration of enzyme molecules, because some enzyme molecules have more than one active site. If the enzyme molecule has one active site, the turnover number is given by turnover number=Rmax[E]t=k2(Rmax is often written as Vmax) If the enzyme molecule has more than one active site, then [E]t is multiplied by the number of active sites to determine its effective concentration. Determine the value of the turnover number of the enzyme carbonic anhydrase, given that Rmax for carbonic anhydrase equals 249 μmol⋅L−1⋅s−1 and [E]t=2.20 nmol⋅L−1 . Carbonic anhydrase has a single active site.

Answer 1

Answer:

Turnover number = 113182s⁻¹

Explanation:

Turnover number is a concept used to know the activity of an enzyme. The higher turnover number, the higher activity of the enzime.

Turnover number is defined as:

Turnover number = Rmax / [E]t

As Rmax is  249 μmol⋅L⁻¹⋅s⁻¹ and [E]t is 2.20 nmol⋅L⁻¹

As 1μmol = 1000nmol, Rmax = 249000 nmol⋅L⁻¹⋅s⁻¹. Replacing:

Turnover number = 249000 nmol⋅L⁻¹⋅s⁻¹ / 2.20 nmol⋅L⁻¹

Turnover number = 113182s⁻¹