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Papessa [141]
3 years ago
11

When an atom _________ an electron, it charge is positive.

Chemistry
1 answer:
Ugo [173]3 years ago
3 0

Answer:

captures

Explanation:

when it captures

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Volume and moles are __________ related. This relationship can be calculated by using ___________ Law.
Kryger [21]

Answer:

The correct answer is - directly; Avogadro’s.

Explanation:

At the same temperature and pressure, gases of the same or equal volume have the same number of molecules. The relation between the moles of the gases and the volume of the gases are indirectly proportional to one another at the same temperature and pressure. This law is called Avogadro's law. In the case of an ideal gas of a particular mass has the volume and moles are directly proportional.

Thus, the correct answer is - directly; Avogadro’s.

6 0
3 years ago
Which of these properties is the best one to use for identification of an element?
katovenus [111]
the number of protons in the atomic nucleus
3 0
3 years ago
There are two open cans of soda on the table one can was just take it on the refrigerator and the other was taken from the cup b
agasfer [191]

The one from the cupboard because it is warmer (has more thermal energy) than the one from the refrigerator. When a liquid becomes warmer, the solubility of a gas becomes lower. Therefore, there is already more CO2 in its gaseous state when the soda is warm.


8 0
3 years ago
Read 2 more answers
9.00 g/h to kilograms per minute
Mkey [24]
9.00g/1hr * 1kg/100g * 1hr/60min = 0.00015kg/min or 1.5 * 10^-4kg/min.
4 0
4 years ago
A balloon is launched when the temperature is 15 oC and the pressure is 0.918 atm. Its volume is 11.1 L. It rises in the air unt
ivann1987 [24]

Answer:

The new volume is 7,606.96 Liter.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas in the balloon = 0.918 atm

P_2 = final pressure of gas in the balloon = 0.0012 atm

V_1 = initial volume of gas in the balloon = 11.1 L

V_2 = final volume of gas in the balloon = ?

T_1 = initial temperature of gas in the balloon = 15^oC=273+15=288K

T_2 = final temperature of gas in the balloon = -15^oC=273-15=258K

Now put all the given values in the above equation, we get:

\frac{0.918 atm\times 11.1 L}{288 K}=\frac{0.0012 atm\times V_2}{258 K}

V_2=\frac{0.918 atm\times 11.1 L\times 258 K}{288 K\times 0.0012 atm}

V_2=7,606.97 L

The new volume is 7,606.96 Liter.

5 0
3 years ago
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