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notsponge [240]
3 years ago
15

17. Which of the following describes a condition in which an individual would not hear an echo?

Chemistry
2 answers:
Fynjy0 [20]3 years ago
7 0
D. <span>A sound wave reaches the ear and the reflected wave reaches the ear less than 0.1 second later.

Just took the Penn Foster test, got it right. =]</span>
ivanzaharov [21]3 years ago
5 0
<span>The right answer is D. In a situation where the sound wave reaches the ear and the reflected wave reaches the ear less than 0.1 seconds later, the individual would not be able to hear an echo. There needs to a far more significant delay between the sound and the reflection of said sound reaching the listener's ear for the echo effect to become apparent.</span>
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Aluminum reacts with chlorine gas to produce aluminum chloride crystals. How many grams of aluminum chloride will be produced if
valina [46]

Answer:

596 g of AlCl₃

Explanation:

The reaction is:

2Al + 3Cl₂  →  2AlCl₃

Firstly we need to determine the limiting reactant and we need to determine the moles of each

135 g . 1 mol / 26.98 g = 5 moles of Al

475 g . 1mol / 70.9 g = 6.7 moles of chlorine

Ratio in the reaction is 3:2

3 moles of chlorine gas need 2 moles of Al to react

Then, our 6.7 moles of gas might react to (6.7 . 2 ) /3 = 4.47 moles of Al

We have 5 moles of Al and we need 4.47 moles, so this is the excess reactant. In conclussion, Cl₂ is the limiting.

2 moles of Al react to 3 moles of gas

Our 5 moles of Al may react to (5 . 3 )/2 = 7.5 moles of gas

It's ok because we only have 6.7 moles, and there is not enough gas.

Now we calculate the product's mass

3 moles of gas can produce 2 moles of salt

Then, our 6.7 moles of gas will produce (6.7 . 2) /3 = 4.47 moles

We convert moles to mass: 4.47 mol . 133.33 g/mol = 596 g of AlCl₃

3 0
2 years ago
A mineral contains only a metal, M, and sulfur. If analysis indicates that a 44.9 g sample of the mineral contains 2.1 g of M, w
taurus [48]

Answer:

15.38 g is the mass for M in the 329 g of sample

Explanation:

Mineral's formula: MS

Our sample weighs 44.9 g

Mass of M: 2.1 g

Our new sample weighs 329 g

We may solve this by a rule of three:

44.9 g of sample contain 2.1 g of M

329 g of sample will contain (329 . 2.1) / 44.9 = 15.38 g

5 0
3 years ago
Read 2 more answers
Describe the preparation of 2.000 L of 0.0500 M AgNO3 (169.87 g/mol) from the primary-standard-grade solid.
Tanzania [10]

Answer:

Transfer 1.6987 grams of AgNO₃ into a mixing container and add solvent up to but not to exceed 2.000 Liters total volume. Mix and apply as needed.

Explanation:

A simple formula for determining the amount of reagent needed for a specified solution from a manufacturer's 'solid' reagent** is ...

grams solute needed = Molarity x Volume of Solution in Liters x Molecular Weight of solute

Determination of mass of solute needed:

∴ grams AgNO₃ needed* = M·V·mol. wt = (0.0500M)(2.000L)(169.87g·mol⁻¹) = 1.6987 grams AgNO₃

*assumes 100% pure reagent.

Preparation:

Transfer 1.6987 grams of AgNO₃ into a mixing container and add solvent up to but not to exceed 2.000 Liters total volume. Mix and apply as needed.

________________________________

NOTE => FYI => If a manufacturer's liquid form reagent is used, one must divide calculated grams by density of liquid supplied and gives volume in milliliters (ml) needed to prepare a specified solution.

Vol reagent needed for soln prep in milliliters = (Molarity·Volume in Liters·formula wt of reagent)/(density of stock liquid concentrate)

That is,  Vol(ml) = [(M)(V)(f.wt.)] / density of stock

Prep: Transfer needed volume (ml) of liquid stock into mixing vessel and add solvent up to but not to exceed total volume of solution needed.

<em>NOTE => Caution when applying to strong acids. 1st add a small quantity of water such that water + volume of acid is less than total volume needed followed by strong acid, then dilute to the needed total volume. Such prevents solution from overheating because of high rate of ionization and flashing out of container.</em>    

5 0
3 years ago
Making homemade ice cream is one of life's great pleasures. fresh milk and cream, sugar, and flavorings are churned in a bucket
crimeas [40]
It should be 13.48%.

 1130g NaCL/7250g Ice + 1130 NaCl=0.1348 x 100%= 13.48%
4 0
3 years ago
Read 2 more answers
Which condition may cause farsightedness?
ozzi
It would be that the cornea is not curved enough, thus not allowing the pupil to expand to perceive further distances clearly. :)

6 0
3 years ago
Read 2 more answers
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