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PilotLPTM [1.2K]
3 years ago
13

The force of gravity pulls down on your house with a total force of 300,000 newtons. The force of gravity pulling down on your h

ouse would be exactly twice as much if your house:
Chemistry
1 answer:
Nataly [62]3 years ago
5 0

Explanation:

The force of gravity acting on an object is given by :

W = F = mg

Where W is the weight of an object

The force of gravity on house is 300,000 N. The force of gravity pulling down on your house would be exactly twice as much if your house has twice as much as mass because force of gravity is directly depends on mass.

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Calculate ΔGrxn at 298 K under the conditions shown below for the following reaction.
algol13

Answer : The value of \Delta G_{rxn} is -24.9 kJ/mol

Explanation :

First we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)

The expression for reaction quotient will be :

Q=\frac{(p_{CO_2})^3}{(p_{CO})^3}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(2.1)^3}{(1.4)^2}

Q=3.375

Now we have to calculate the value of \Delta G_{rxn}.

The formula used for \Delta G_{rxn} is:

\Delta G_{rxn}=\Delta G^o+RT\ln Q    ............(1)

where,

\Delta G_{rxn} = Gibbs free energy for the reaction  = ?

\Delta G_^o =  standard Gibbs free energy  = -28.0 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

Q = reaction quotient = 3.375

Now put all the given values in the above formula 1, we get:

\Delta G_{rxn}=(-28.0kJ/mol)+[(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln (3.375)

\Delta G_{rxn}=-24.9kJ/mol

Therefore, the value of \Delta G_{rxn} is -24.9 kJ/mol

5 0
3 years ago
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