Answer:
A) μ = A.m²
B) z = 0.46m
Explanation:
A) Magnetic dipole moment of a coil is given by; μ = NIA
Where;
N is number of turns of coil
I is current in wire
A is area
We are given
N = 300 turns; I = 4A ; d =5cm = 0.05m
Area = πd²/4 = π(0.05)²/4 = 0.001963
So,
μ = 300 x 4 x 0.001963 = 2.36 A.m².
B) The magnetic field at a distance z along the coils perpendicular central axis is parallel to the axis and is given by;
B = (μ_o•μ)/(2π•z³)
Let's make z the subject ;
z = [(μ_o•μ)/(2π•B)] ^(⅓)
Where u_o is vacuum permiability with a value of 4π x 10^(-7) H
Also, B = 5 mT = 5 x 10^(-6) T
Thus,
z = [ (4π x 10^(-7)•2.36)/(2π•5 x 10^(-6))]^(⅓)
Solving this gives; z = 0.46m =
i believe it is c but i could be wrong. (i’m sorry if i am)
Answer:
C
Explanation:
That is where the most heat and light is showing on this diagram.
When a current is established in a closed conducting loop , we use ammeter. Due to this resultant potential developed detected by voltmeter.
- When current flows through loop , it gets conducted.
- Due to this Electric field is generated . This happens due to induced magnetic field.
- The free electrons were at rest until current is there , still ammeter detects some deflection.
- This deflection is due to zero current.
- Due to magnetic field , current in coil changes.
- Mathematically,
- The presence of conducting loop is not necessary for having electric field.
i=0.63 io
To know more about voltmeter-
<u>brainly.com/question/1511135</u>
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