Answer:
The final charges of each sphere are: q_A = 3/8 Q
, q_B = 3/8 Q
, q_C = 3/4 Q
Explanation:
This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.
Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point
q_A = Q / 2
q_B = Q / 2
Now sphere A touches sphere C, ending with half the charge
q_A = ½ (Q / 2) = ¼ Q
q_B = ¼ Q
Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge
q = Q / 4 + Q / 2 = ¾ Q
This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q
q_A = 3/8 Q
q_B = 3/8 Q
The final charges of each sphere are:
q_A = 3/8 Q
q_B = 3/8 Q
q_C = 3/4 Q
Answer:
Explanation:
Sum moments about the rear tires to zero to find the force on the front tires
F[3.13] - 1540(9.81)[3.13 - 1.09] = 0
F = 9,846
so each front wheel supports half of that weight
F/2 = 9846/2 = 4,923 ≈ 4920 N
Sum vertical forces to zero
9,846 + R - 1540(9.81) = 0
R = 5,261
so each rear wheel supports half of that weight
R/2 = 5261/2 = 2630.52 ≈ 2630 N
Answer:
Tangential speed = R * w where w is the angular speed
For a wheel v = .114 m * 6.53 / sec = .744 m/s
Note that this is the tangential speed - If the wheel were moving at speed V then as viewed from the ground you have
top V + v
bottom V - v
That is the wheel also has speed due to the speed of the axle (axis of rotation)
Answer:
392°F
Explanation:
200°C × 9/5) + 32 = 392°F
Answer:
B :)
Explanation:
:) JUST TRUST ME I GOT IT CORRECT