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UNO [17]
3 years ago
9

How large a force F is needed in the figure to pull out the 6.0 kg block with an acceleration of 1.50m/s^2 if the coefficient of

friction at its surfaces is 0.40?​
Physics
1 answer:
zheka24 [161]3 years ago
6 0

Answer:

32.52 N

Explanation:

F-F' = ma.................. Equation 1

Where F = Force needed to pull the block, m = mass of the block, a = acceleration of the block, F' = Frictional force of the surface acting on the blcok

F = ma+F'

But,

F' = μmg

Where g = acceleration due to gravity, μ = coefficient of static friction

F = ma+μmg.................... Equation 2

Given: m = 6.0 kg, a = 1.5 m/s², μ = 0.40

Constant: g = 9.8 m/s²

Substitute these values into equation 2

F = 6(1.5)+6(9.8)(0.4)

F = 9+23.52

F = 32.52 N

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Part A
Basile [38]

The relationships to determine the number of calories to change 0.50 kg  of 0°C ice to 0°C ice water is 1,080,000 cal.

<h3>How does heating ice that is at C affect it?</h3>

Ice melts and becomes liquid water at 0 degrees Celsius. Once all of the ice has been entirely transformed into liquid water, the temperature of the remaining ice begins to increase once more (in °C), continuing to rise until it reaches 100 °C, where it then stabilizes.

The water turns into steam when it reaches a temperature of 100 °C (D).

Water has a fusion latent heat of fusion of 80 cal/g.

Water has a 1 cal/g-C specific heat.

Water has a 540 cal/g latent heat of vaporization.

In light of this, the total amount of heat needed is 1500 g [(80 cal/g) + (1 cal/g-C)(100 - 0)C + (540 cal/g)] = 1500 g [(720 cal/g)] = 1,080,000 cal.

To learn more about Vaporization refer to:

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6 0
1 year ago
Which statement accurately describes the charge of the nucleus of an atom?
Aleksandr [31]

Answer:

A. The nucleus can be either positively charged or neutral.

Explanation:

The nucleus of an atom contains protons and neutrons only. Whereas electrons revolve around the nucleus. Protons are positively charged, neutrons have no charge and electrons are negatively charged.

3 0
3 years ago
An 12 N force is applied to a 1 kg object. What is the magnitude of the objects acceleration?
Sauron [17]

Answer:

a=12 m/s²

Explanation:

Newton's second law of motion states that the acceleration of a body is directly proportional to the force applied and takes place in the direction of force.

This can be summarized as: F=ma, where m is the mass of the object on which force F acts. a is the acceleration due to the force applied.

12N= 1kg×a

a=12N/1kg

a=12m/s²

6 0
4 years ago
Which of the following describe advantages of using radio waves over other electromagnetic waves to transmit information to Eart
Whitepunk [10]

The correct options are:

D

"Radio waves have a lower frequency, which makes them safer for humans."

B

"Radio waves take less energy to produce."

<h3>Why do we radio waves over other electromagnetic waves to transmit information to Earth? </h3>

Radio waves are electromagnetic waves with frequencies on the range from 10 KHz to 10 THz.

Now, remember that all electromagnetic waves have the same speed, which is the speed of light, and the energy of a wave is proportional to its frequency.

Particularly, we can see that radio waves have small frequencies (smaller than infrared light) so these waves carry very little energy.

With that in mind, the correct options are.

D

"Radio waves have a lower frequency, which makes them safer for humans."

B

"Radio waves take less energy to produce."

These are the two main reasons of why we use radio waves.

If you want to learn more about electromagnetic waves.

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4 0
2 years ago
How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 39 j of work?
sdas [7]
The work done by the battery is equal to the charge transferred during the process times the potential difference between the two terminals of the battery:
W=q \Delta V
where q is the charge and \Delta V is the potential difference.

In our problem, the work done is W=39 J while the potential difference of the battery is \Delta V = 9.0 V, so we can find the charge transferred by the battery:
q= \frac{W}{\Delta V}= \frac{39 J}{9.0 V}=4.33 C
3 0
4 years ago
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