For the hardy weinberg eqn ;
it is D ! so option second is correct !
and for the second one, it is mutation !
if you need explanation, comment ! or it is OK !
Answer:
There are no chances for this couple to have a child with Tay-Sachs disease. 0% of the possibilities.
Explanation:
Tay-Sachs disease affects the nervous system and is potentially mortal. It is transmitted from parents to progeny. Tay-Sachs is caused by a defective gene in the 15 chromosome.
The child that recesives two coppies of this defective gene, one from the mother and one from the father, results sick. <u>But if only one of the parents transmits the gene, then the child will be a carrier.</u> This child won't be sick but will transmit the gene to his/her own progeny.
<u>Available data</u>:
- The allele for tay-sachs is a recessive allele, "t"
- Tim McGraw to determine is a carrier, Tt
- Tim´s wife is not a carrier, TT
<u>Cross:</u>
Parental) TT x Tt
Gametes) T T T t
Punnet square) T T
T TT TT
t Tt Tt
F1) Progeny genotype: 2/4= 1/2 normal, TT
2/4= 1/2 Carrier, Tt
0/4= 0 Sick, tt
What are the chances they could have a child with Tay-Sachs?
There are 0% of the possibilities that this family will get a sick child.
The answer is one trait. In Codominant alleles, neither allele is dominant over the other. Both alleles are expressed equally hence no recessive or dominant phenotypes. An example of that of fur color in rabbits where one parent with black fur color and the other with white fur color will produce offspring of black and white fur color. This should not be confused with incomplete dominance whre the two alleles blend in phenotype.Example of incomplete dominance is a parent with straight hair in humans and another with curled hair will produce wavy hair offsprings.
Active enzyme + substrate > product + active enzyme
