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3 years ago

Round the factors to estimate the products. 697 x 82=

Mathematics

2 answers:

Komok [63]3 years ago

8 0

697 x 82 = 56,154
700 x 80= 56,000

krek1111 [17]3 years ago

3 0

700*80=56000 while estimating your answer you round it to the nearest hundred or 10 depending on the number in this case it will be 700 rounding 697 and 80 rounding 82 to the nearest tenth

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Answer:

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Step-by-step explanation:

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3 years ago

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There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of

Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

$AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta$ (1)

Where:

$AC$ - The distance from A to C, measured in miles.

$AB$ - The distance from A to B, measured in miles.

$BC$ - The distance from B to C, measured in miles.

$\theta$ - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

$AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta$

$\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}$

$\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right)$ (2)

If we know that $BC = 7\,mi$ , $AB = 8\,mi$ , $AC = 5\,mi$ , then the bearing from island B to island C:

$\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]$

$\theta \approx 38.213^{\circ}$

The bearing needed to navigate from island B to island C is approximately 38.213º.

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3 years ago

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Levart [38]

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Therefore, angle C is also 74°.

The sum of the interior angles of a triangle is equal to 180°.
Thus,
180° = ∡A + ∡B + ∡C
180° = 74° + ∡B + 74°
180° = 148° + ∡B
∡B = 180° - 148°
∡B = 32°

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3 years ago

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erastovalidia [21]

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