a. It will take 24.6 s for the police officer to reach the speeder
b. The police speed will be 66.42 m / s at this time
<h3>Further explanation</h3>
Regular straight motion is the motion of objects on a straight track that has a fixed speed
Formula used
S = distance = m
v = speed = m / s
t = time = seconds
Straight motion changes regularly are the straight motion of objects that have a fixed acceleration
Formula used
V = vo + at
Vt² = vo² + 2as
St = distance on t
vo = initial speed
vt = speed on t
a = acceleration
The full version of the question might be like this:
A speeding motorist traveling 120 km / h passes a stationary police officer. The officer immediately begins pursuit at a constant acceleration of 10.8 km / h / s (note the mixed units).
(a) How much time will it take for the police officer to reach the speeder, assuming that the speeder maintains a constant speed?
(b) How fast will the police officer be traveling at this time?
A speeding motorist traveling 120 km/h (fixed speed) shows irregular straight motion
Whereas The officer immediately begins pursuit at a constant acceleration of 10.8 km/h/s showing that straight motion changes irregularly
So that the officer can catch A speeding motorist, the distance achieved by both of them is the same and also with the same time
- 1. the distance achieved by the speeding motorist
v = 120 km / h = 33.3 m / s
S1 = v. t
S1 = 33.3t
- 2. the distance reached by the officer
vo = 0
a = 10 km / h / s = 2.7 m / s²
S2 = vot + 1/2 at²
S2 = 0 + 1/2 .2.7t²
S2 = 1.35t²
- a. The distance traveled when the two meets are the same, so the time of both can be determined
S1 = S2
33.3t = 1.35t²
t = 24.6 s
Vt = vo + at
Vt = 0 + 2.7.24.6
Vt = 66.42 m / s
<h3>Learn more</h3>
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resultant velocity
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the average velocity
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Keywords: the officer, a speeding motorist
, fixed acceleration, fixed speed