Question

There is a 90 kg woman attached at the end of a bungee cord (k = 35 N/m) that is experiencing simple harmonic motion. How long does it take the woman to complete one cycle?

Answer 1

Answer:

The value is $T =10.1 \ s$

Explanation:

From the question we are told that

    The mass of the woman is  $m = 90 \ kg$  

    The spring constant of the bungee cord is  $k = 35 \ N/ m$

Generally the period of the oscillation (i,e time taken to complete on  cycle ) is mathematically represented as

            $T = 2 \pi * \sqrt{ \frac{m}{k} }$

=>      $T = 2 * 3.142 * \sqrt{ \frac{90 }{ 35} }$

=>      $T =10.1 \ s$