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MAVERICK [17]
2 years ago
7

A student wearing frictionless in-line skates on a horizontal surface is pushed, starting from rest, by a friend with a constant

force of 60 N. How far must the student be pushed, so that her final kinetic energy is 300J?
Physics
2 answers:
grin007 [14]2 years ago
8 0

Answer:

Physics

Explanation:

Explanation:

We can use the Theorem of Work (W) and Kinetic Energy (K):

W=ΔK=Kf−Ki

it basically tells us that the work done on our system will show up as change in Kinetic Energy:

We know that the initial Kinetic Energy, Ki=12mv2i, is zero (starting from rest) while the final will be equal to 352J; Work will be force time displacement. so we get:

F⋅d=Ff

45d=352

and so:

d=35245=7.8≈8m

galben [10]2 years ago
3 0

Answer:

d= 352/45=7.8≈ 8m

Explanation

We can use the Theorem of Work (W) and Kinetic Energy (K):

W=ΔK=k <em>f</em> - k <em>i </em>, it is basically tells us that the work done on our system will show up as change in Kinetic Energy:We know that the initial Kinetic Energy, k<em>i</em> =1/2 <em>mv</em> 2/i, is zero (starting from rest) while the final will be equal to 352J; Work will be force time displacement. so we get: F . d = F<em>f</em>

45<em>d</em>= 352 and so d= 352/45=7.8 ≈ <em>8m</em>

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