1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leno4ka [110]
3 years ago
12

How do you think car makers can design cars to limit cell phone distractions?

Physics
1 answer:
Dafna11 [192]3 years ago
8 0

I have two (2) brilliant ideas:

1). Inside the metal that the body of the car is made of, and also between the two sheets of glass that the windows are made of, install a thin layer of material that absorbs RF (radio-wave) energy . . . like the material in the glass window of your microwave oven.  Then, no radio waves from the cellular base station can get INTO the car, and no radio waves from your phone can get OUT of the car.  The phone can't make a connection to the cellular network, you can't make or receive calls, and you can't connect to Instagram or Brainly, so you might as well just turn it off and save your battery until next time you're outside your car.

2). Somewhere inside the car, like under the dash or in the glove box, install a teeny tiny radio receiver that can recognize the signals coming OUT of your phone.  Connect it to the car's electrical system so that when it hears signals from phones inside the car, it it shuts down the car's motor so you can't start or drive. The car only works when phones inside the car are either turned off or in Airplane Mode.

My ideas are so brilliant that I really should patent them, or copyright them, or whatever you do so that other people have to pay you to use your idea. But if you want to use them, that's OK.  Just go ahead. I won't mind.

You might be interested in
As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff ideal sprin
shepuryov [24]

Answer:

The magnitude of force must you apply to hold the platform in this position = 888.89 N

Explanation:

Given that :

Workdone (W) = 80.0 J

length x = 0.180 m

The equation  for this  work done by the spring is expressed as:

W = \frac{1}{2}k_{eq}x^2

Making the spring constant k_{eq} the subject of the formula; we have:

k_{eq} = \frac{2W}{x^2}

Substituting our given values, we have:

k_{eq} = \frac{2*80}{0.180^2}

k_{eq} = 4938.27 \ N.m^{-1}

The magnitude of the force that must be apply  to the hold platform in this position is given by the formula :

F = k_{eq}x

F = 4938.27*0.180

F = 888.89 N

6 0
3 years ago
a solution made by dissolving 116 g of CaCl2 in 64 g of water has a density of 1.180 g/ml at 20 degrees celsius what is the mola
Makovka662 [10]

Answer:

The molarity of CaCl2 in the solution is 4.94 M

Explanation:

First of all you need to calculate CaCl2 mass.

You have one atom of Ca = 40.07 g/mol and two atoms of Cl = 35.45 g/mol so the molecule has a mass of 110.97 g/mol.

Now, knowing that your solution will have a mass of 64 grams of water + 116 grams of CaCl2 = 180 grams, you can calculate its volume, knowing that density = mass/volume

density x mass = volume --> 1,180 g/ml x 180 g = 212.4 ml

In 212.4 ml, you have 116 grams of CaCl2. You can calculate how many moles of CaCl2 you have:

110.97 g ------ 1 mol

116 g -------- x = (116 g x 1 mol) / 110.97 g =  1.05 moles

The molarity in a solution equals how many moles of a certain solute you have in 1000 ml of solution. In this solution, you have 1.05 moles in 212.4 ml, so in 1000 ml you will have:

212.4 ml ------- 1.05 moles

1000 ml -------- x = (1000 ml x 1.05 moles) / 212.4 ml = 4.94 moles.

This means the molarity of CaCl2 in the solution is 4.94 M.

4 0
3 years ago
11. You are in the frozen food section of the grocery store and you notice that your hand gets cold when you place it on the gla
Flauer [41]

Explanation:

it happens in the morning time

3 0
3 years ago
You are at home in your air conditioned garage. You are planning a family road trip from New York to Florida. You are lnfating t
Alex
The tires deflated and so that means that you won’t be able to travel
6 0
3 years ago
A 1kg box is pushed on a flat surface that is 250m long. The box is initially at rest and then pushed with a constant Net force
sasho [114]

Answer:

C) 50 m/s

Explanation:

With the given information we can calculate the acceleration using the force and mass of the box.

Newton's 2nd Law: F = ma

  • 5 N = 1 kg * a
  • a = 5 m/s²

List out known variables:

  • v₀ = 0 m/s
  • a = 5 m/s²
  • v = ?
  • Δx = 250 m

Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:

  • v² = v₀² + 2aΔx

Substitute known values into the equation and solve for v.

  • v² = (0)² + 2(5)(250)
  • v² = 2500
  • v = 50 m/s

The final velocity of the box is C) 50 m/s.

7 0
3 years ago
Other questions:
  • even though the sun has _____mass than earth the moon orbits earth because it's closer to earth than to the sun
    12·2 answers
  • A basketball player throws a ball at 60° to the horizontal at a net 4.0m away. The height of the net is 3.3m. The ball leaves hi
    10·1 answer
  • 1. what are valence electrons?
    11·2 answers
  • A student decides to give his bicycle a tune up. He flips it upside down (so there’s no friction with the ground) and applies a
    13·1 answer
  • Un auto recorre una carretera en línea recta de 10km y tarda 8 minutos ¿Cual es su velocidad en km/h?
    14·1 answer
  • Show that a light ray that strikes two mutually perpendicular reflecting surfaces is reflected back exactly parallel to the dire
    5·1 answer
  • How would the atmosphere of earth differ if the earth was much larger
    9·2 answers
  • The ability of atoms to attract electrons from surrounding atoms is called
    11·2 answers
  • An electric charge of 1 microcoulomb is affected by an electric field of intensity 1000 newtons per coulomb at a point, then thi
    13·1 answer
  • Please help I have no idea how to do this
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!