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Korolek [52]
4 years ago
9

What fractions are equivalent to 1.27 repeated

Mathematics
1 answer:
kramer4 years ago
3 0
<span>Let x equal your repeating decimal. Call this equation x = 1.273
</span><span>Multiply both sides of your previous expressions by 100. Call this equation 100x = 127.273
</span><span>Subtract 1 from both sides of the equation to get 99x = 126.
</span><span>Divide both sides of the equation by 99 to get 126/99.
</span><span>126/99 reduced is to its lowest terms is 1 and 3/11.
</span>
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Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

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\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

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Step-by-step explanation:

                                           

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GoOd ViBeS oNlY

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