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alexandr402 [8]
4 years ago
5

Neon signs require 12 kv for their operation. to operate from a 244 v line, what must be the ratio of secondary to primary turns

of the transformer?

Physics
1 answer:
jek_recluse [69]4 years ago
3 0
The answer would be 49. Check the attach file for solution.

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Satellites transfer all our information from ken mobile device to another
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Which type of rock contains minerals arranged in crystals and forms when molten rock cools and turns solid?
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The answer to ur question is: C
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The figure below is a graph of net force vs. the acceleration of an object. Use a graph to determine the mass of the object.
kotegsom [21]

Answer:scattered plot

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6 0
3 years ago
When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the
Brrunno [24]

Answer:

D=387.28m

Explanation:

At the moment where the toss is made X_R = X_G, so we need both equations:

For the red car:

X_R=\frac{a_R*t^2}{2}   With initial speed of 0 and acceleration of 6.12m/s^2.

For the green car:

X_G=Xo + V_G*t   With V_G = 60km/h*\frac{1000m}{1km} * \frac{1h}{3600s} = 16.66m/s   and Xo = 200m

Since both positions will be the same:

\frac{a_R*t^2}{2}=Xo+V_G*t   Solving for t:

t1 = -5.8s  and   t1 =11.25s

Replacing t = 11.25 on either equation to find the displacement:

D = X_R = \frac{a_R*t^2}{2} = 387.28m

3 0
4 years ago
A 2000 kg truck is traveling at 5 m/s and collides with a 1000 kg car that is not moving. After the collision, the 2000 truck st
sp2606 [1]

Answer:

A) 10 m/s

Explanation:

We know that according to conservation of momentum,

m1v1 + m2v2 = m1u1 + m2u2  ..............(equation 1)

where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.

From the given data

If truck and car are two bodies

truck :       m1 = 2000 Kg           v1 = 5 m/s                u1 = 0

car    :        m2 = 1000 kg           v2 = 0                      u2 = ?

final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.

substituting the values in equation 1, we get

(2000 x 5) + 0 = 0 + (1000 x u2)

u2 = \frac{2000}{1000} x 5

    = 10 m/s

Hence after collision, car moves at a velocity of 10 m/s

3 0
3 years ago
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