Question

Two trains, each having a speed of 33 km/h, are headed at each other on the same straight track. A bird that can fly 60 km/h flies off the front of on train when they are 60 km apart and heads directly for the other train. On reaching the other train, the (crazy) bird flies directly back to the first train, and so forth. What is the total distance the bird travels before the trains collide?

Answer 1

Answer:

66 km

Explanation:

Given that:

The speed of the two trains = 33 km/h

The speed of the bird = 60 km/h

The distance apart between the two trains =  60 km

From the given information, we are being told that the two trains are going at the same speed. Therefore, they will definitely collide at 30 km

We know that:

speed  of the train = distance traveled × time

Making the time t the subject of the formula:

time = speed of the train / distance traveled

time = 30 km / 33 km/h

time = 0.909 / hr

Thus, the bird flying at a given speed of 60 km/h in a time of 0.909 / hr will cover a total distance of :

distance (d) = speed of the bird/ time

distance (d) = $\dfrac{60 \ km/hr}{0.909 \ /hr}$

distance (d) = 66 km